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I have a problem i cant figure out. The sum of two numbers…

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I have a problem i cant figure out. The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other. Find the numbers.

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I figure it would be something like a + b = 15

Tutor's Assistant: Is there anything else important you think the Math Tutor should know?

3a = 5b - 11

Submitted: 11 months ago.Category: Pre-Calculus
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Answered in 2 minutes by:
9/6/2017
Tutor: GLENN GILONGOS,
 replied 11 months ago
GLENN GILONGOS
Category: Pre-Calculus
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Hi

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Tutor: GLENN GILONGOS,
 replied 11 months ago

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Tutor: GLENN GILONGOS,
 replied 11 months ago

Solution:
.
a + b = 15 -> equation 1
5a - 3b = 11 -> equation 2
.
multiply equation one by 3 both sides, you will get 3(a + b) = 3(15)
--> 3a + 3b = 45
.
then add this to equation two:
.
3a + 3b = 45
+ 5a - 3b =11
-------------------------
8a = 56

divide both sides by 8:
.
8a = 56
8a/8 = 56/8
a = 7
.
back substitute a = 7 in the original equation one:
.
a + b = 15 if a = 7, then
7 + b = 15
b = 15 - 7
b = 8

answers: a = 7, b = 8
.


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