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give me a minute and I'll post the solution
ok no worries.
sin 2x sin x-cos x = 02sinx cosx sin x-cos x = 0cosx (2(sinx)^2 -1)=0so you have two options:1) cos x=0 ==> x= Pi/2 or 3Pi/22) 2(sinx)^2 -1=0 ==> sin x = 1/sqrt(2) ==> x=PI/4 or 3Pi/4Answer: x= Pi/2, 3Pi/2,PI/4, 3Pi/4
hope this helps
actually there are more: with negative
3) 2(sinx)^2 -1=0 ==> sin x = -1/sqrt(2) ==> x=5PI/4 or 7Pi/4
so the complete answer is this:
Answer: x= Pi/2, 3Pi/2,PI/4, 3Pi/4, 5PI/4, 7Pi/4
let me know if there are any questions, it will be my pleasure to assist.
i have different ones should i stay on this or just go to input a new question
Pleas eopen a new thread and type "for david" I'l pick