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If P(A)=0.50, P()=0.40, and P(AuB)=0.88, then P(/A)=

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If P(A)=0.50, P(B)=0.40, and P(AuB)=0.88...
If P(A)=0.50, P(B)=0.40, and P(AuB)=0.88, then P(B/A)=
Submitted: 2 years ago.Category: Math Homework
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6/6/2015
Math Tutor or Teacher: Ashok Kumar, Electrical Engineer replied 2 years ago
Ashok Kumar
Ashok Kumar, Electrical Engineer
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Customer reply replied 2 years ago
Thank you, Ashok. Would you please explain so I can try to answer other questions using your example? Thank you!
Math Tutor or Teacher: Ashok Kumar, Electrical Engineer replied 2 years ago
P(A U B) = P(A) + P(B) - P(A ∩ B)
0.88 = 0.5+0.4- P(A ∩ B)
Or, P(A ∩ B)= 0.5+0.4 - 0.88 = 0.02
P(B/A) = P(A ∩ B)/P(A)
= 0.02/0.5
= 0.04
Kindly let me know for any clarification.
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Customer reply replied 2 years ago
So, you treat it like an equation in Algebra, basically, adding a negative to the other side to balance out the probability?
Math Tutor or Teacher: Ashok Kumar, Electrical Engineer replied 2 years ago
Actually it is conditional probability problem. We have find out P(A∩B)to determine P(B/A) and this is what I have done.
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Math Tutor or Teacher: Ashok Kumar, Electrical Engineer replied 2 years ago
Kindly rate the answer if no further clarification is needed.
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