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mean = 1*0.5+2*0.3+3*0.2=1.7now calculte the expected x^21^2*0.5+2^2*0.3+3^2*0.2=3.5hence the standard deviation is:stdev = sqrt(3.5-1.7^2)=0.781
Answer: mean = 1.7, standard deviation = 0.781
Not understanding the second half of the answer.
to get the standard deviation
you need to calculate the variance first
recall that variance is defined as a difference between the mean of the squares: 1,4,9
and the square of the mean 1.7
the mean of the squares is found to be 3.5
and the variance is hence 3.5-1.7^2 = 0.61
now taking the square root of this we get standard deviation = √0.61 =0.781
is it clear now?
I am trying to understand is (1)^2(0.5) or (1)(0.5)^2?
I have to show all of my steps
it is one squared times point five
because you need he mean of the squares
the numbers you have are 1,2,3 so the squares are 1, 4, 9
does it make sense now?