Math Homework

Ask Math Questions. Get Help With Your Math Homework

Connect one-on-one with {0} who will answer your question

Related Math Homework Questions
Solve equations / uneven contacts. a) 20cos2x 3cosx + - 2
Solve equations / uneven contacts. a) 20cos2x 3cosx + - 2 = 0 b) 3tan2x - 8tanx - 3 = 0 c) (cosx - 1/3) (cosx + 1/3) / (cosx - 1/2) (cosx + 1/2) ≥ 0 d) (tanx - 2) / (2tanx + 3) <0… read more
Mijcar
Mijcar
Consultant
Master's Degree
67 satisfied customers
solve the equations: a) 20cos2x + 3cosx – 2 = 0 b) 3tan2x
solve the equations: a) 20cos2x + 3cosx – 2 = 0 b) 3tan2x – 8tanx – 3 = 0 c) (cosx - 1/3)(cosx + 1/3)/(cosx - 1/2)(cosx + 1/2) ≥0 d) (tanx – 2)/(2tanx + 3) < 0… read more
Trigeoscal
Trigeoscal
College Math Professor
Master's Degree
960 satisfied customers
Sandyhya, thanks again but I have a couple more questions: 1)
Sandyhya, thanks again but I have a couple more questions: 1) Verify the identity: Cos (x - PI/4) = Sqrt2/2 (Cos x + sin X) -Not sure if I'm doing this correct, but I come up with no Identity 2) Use a… read more
Sandhya
Sandhya
Master's Degree
5,178 satisfied customers
For David: As you assisted with a previous problem, I would
For David: As you assisted with a previous problem, I would like to follow up with another question that I have more detail for: Solve for x; 0 ≤ x < 360 sin2x = cosx 2sinxcosx - cosx = 0 cosx (2si… read more
David
David
Post-Doctoral Degree
Post-Doctoral Degree
2,310 satisfied customers
Determine the general solution for 2(cos^2)x - 5cosx12 0
Determine the general solution for: 2(cos^2)x - 5cosx12 = 0? (MULTIPLE CHOICE)? Determine the general solution for: 2(cos^2)x - 5cosx12 = 0? (MULTIPLE CHOICE)? a) 1.05 + npi, 4.19 + npi b) 1.05 + 2npi… read more
akch2002
akch2002
Master's Degree
3,041 satisfied customers
Factor then simplify (2tan^2-5 tan x - 3)/(4sin x - 16)
Factor then simplify: (2tan^2-5 tan x - 3)/(4sin x - 16) multiply by (sin^2 x - 16)/(2tan x +1)… read more
Sandhya
Sandhya
Master's Degree
5,178 satisfied customers
How do I (1) prove cos (x + Pi/2) -sinx (2) simplify (tanx+1)square
How do I (Question1) prove cos (x + Pi/2)=-sinx and (Question2) simplify (tanx+1)square times cosx… read more
Dr. Dan
Dr. Dan
Doctoral Degree
912 satisfied customers
Dr. Dan, br hi, we are given the problem br br y + 4y
Dr. Dan, hi, we are given the problem y'' + 4y = 4 cos(2x) and they want us to find what the general solution is. heres my work: they gave us a hint saying we can replace cos2x with e^(2ix), i being t… read more
Dr. Dan
Dr. Dan
Doctoral Degree
912 satisfied customers
find dy/dx if 1/3*x^3 + 2x +4xsin(X) +4 cos(X) + sin(2x)
find dy/dx if 1/3*x^3 + 2x +4xsin(X) +4 cos(X) + sin(2x) and prove that dy/dx = {x+2cos(X)}^2… read more
ck_mba
ck_mba
Computer Engineer
Master's Degree
1,397 satisfied customers
1). Prove the identity cos 3 - cos 7 / sin 7 + sin 3
1). Prove the identity cos 3? - cos 7? / sin 7? + sin 3? = tan 2? 2). Prove the identity cos 3? = 4 cos^3 ? - 3 cos ? 3). Solve the following giving answer in radian in the range 0 to 2p (pi): a). cos… read more
Jim C
Jim C
Master's Degree
523 satisfied customers
hi how do i solve this trig equation relative to the unit circle
hi how do i solve this trig equation relative to the unit circle 2cos^(2)x+cosx-1=1 and this one secx=tanx=1 and 2sin^(2)2x=1… read more
Jim C
Jim C
Master's Degree
523 satisfied customers
solve the equation cosx + cos2x 0 for 0 is less than
solve the equation cosx + cos2x = 0 for 0 is less than or equal to x which is less than or equal to 360 degrees… read more
Ben Brown
Ben Brown
Bachelor's Degree
512 satisfied customers
Calculus - tan x and sec x substitutions Could someone please
Calculus - tan x and sec x substitutions? Could someone please start me off/show me how this is done. Just the answer will not help me as I am trying to learn it as part of an exam revision schedule. … read more
Scott
Scott
MIT Graduate
Master's Degree
16,058 satisfied customers
I am trying to solve (sinx)^2 2tanx and (cosx)^2 sinx.
I am trying to solve (sinx)^2 = 2tanx and (cosx)^2 = sinx. For the 2nd equation I thought I could substitute 1-(sinx)^2 for (cosx)^2 and solve by quadratic formula. Is that correct? I don't know about… read more
Elizabeth
Elizabeth
Master's Degree
534 satisfied customers
1. A lookout on a boat sailing directly away from a 120 building
1. A lookout on a boat sailing directly away from a 120' building takes two sightings of the top of the building. The first has an angle of elevation of 34 degree and the second an angle of elevation … read more
Ramanujam
Ramanujam
Master's Degree
16 satisfied customers
Help me Scottsinct- youre my only hope! Ive solved these
Help me Scottsinct- you're my only hope! I've solved these problems but am not getting the correct answers. Can you point out where I'm going wrong? For the method, I need to use Trig Identities, Doub… read more
Scott
Scott
MIT Graduate
Master's Degree
16,058 satisfied customers
1.Find the area of the following triangles (use logarithms) a.
5.Verify the following identities: a. sin 2x= 2(tan x)/(1 + tan^2 x) b. (sin 2 theta)/(sin theta) - (cos 2 theta )/(cos theta) = sec theta c. sin ( x+y) cos (x-y) + cos (x+y) sin (x-y) = sin 2x d. cos… read more
Greg
Greg
Master's Degree
1,292 satisfied customers
show work 1) verify sin(x+y)cos(x-y)+Cos(x+y)sin(x-y) sin2x
show work 1) verify sin(x+y)cos(x-y)+Cos(x+y)sin(x-y) =sin2x B) cos2x=(cot^2x-1)/(cot^2x+1) 2)Simplify to involve a function of only one angle a)(sin80-sin10)/ (sin80+10) B)(sin130+sin20)/(cos130+cos2… read more
Greg
Greg
Master's Degree
1,292 satisfied customers
Disclaimer: Information in questions, answers, and other posts on this site ("Posts") comes from individual users, not JustAnswer; JustAnswer is not responsible for Posts. Posts are for general information, are not intended to substitute for informed professional advice (medical, legal, veterinary, financial, etc.), or to establish a professional-client relationship. The site and services are provided "as is" with no warranty or representations by JustAnswer regarding the qualifications of Experts. To see what credentials have been verified by a third-party service, please click on the "Verified" symbol in some Experts' profiles. JustAnswer is not intended or designed for EMERGENCY questions which should be directed immediately by telephone or in-person to qualified professionals.

JustAnswer in the News:

Ask-a-doc Web sites: If you've got a quick question, you can try to get an answer from sites that say they have various specialists on hand to give quick answers... Justanswer.com.
JustAnswer.com...has seen a spike since October in legal questions from readers about layoffs, unemployment and severance.
Web sites like justanswer.com/legal
...leave nothing to chance.
Traffic on JustAnswer rose 14 percent...and had nearly 400,000 page views in 30 days...inquiries related to stress, high blood pressure, drinking and heart pain jumped 33 percent.
Tory Johnson, GMA Workplace Contributor, discusses work-from-home jobs, such as JustAnswer in which verified Experts answer people’s questions.
I will tell you that...the things you have to go through to be an Expert are quite rigorous.

What Customers are Saying:

Wonderful service, prompt, efficient, and accurate. Couldn't have asked for more. I cannot thank you enough for your help.

Mary C.Freshfield, Liverpool, UK

This expert is wonderful. They truly know what they are talking about, and they actually care about you. They really helped put my nerves at ease. Thank you so much!!!!

AlexLos Angeles, CA

Thank you for all your help. It is nice to know that this service is here for people like myself, who need answers fast and are not sure who to consult.

GPHesperia, CA

I couldn't be more satisfied! This is the site I will always come to when I need a second opinion.

JustinKernersville, NC

Just let me say that this encounter has been entirely professional and most helpful. I liked that I could ask additional questions and get answered in a very short turn around.

EstherWoodstock, NY

Thank you so much for taking your time and knowledge to support my concerns. Not only did you answer my questions, you even took it a step further with replying with more pertinent information I needed to know.

RobinElkton, Maryland

He answered my question promptly and gave me accurate, detailed information. If all of your experts are half as good, you have a great thing going here.

DianeDallas, TX

< Previous | Next >

Meet the Experts:

Manal Elkhoshkhany

Manal Elkhoshkhany

Bachelor's Degree

153 satisfied customers

I have completed my BA degree in 1988, and graduated with a GPA of 4.0.

Thilaan

Thilaan

Master's Degree

126 satisfied customers

I have done Masters.

Mr. Gregory White

Mr. Gregory White

Master's Degree

113 satisfied customers

M.A., M.S. Education / Educational Administration

rajeevanpillai

rajeevanpillai

Master's Degree

88 satisfied customers

M.Sc Statistics MPhil Statistics

Dr Arthur Rubin

Dr Arthur Rubin

Doctoral Degree

76 satisfied customers

Ph.D. in Mathematics, California Institute of Technology

JACUSTOMER-yrynbdjl-

JACUSTOMER-yrynbdjl-

Master's Degree

49 satisfied customers

I have taught college Mathematics for the past 10 years.

SusanAthena

SusanAthena

Master's Degree

41 satisfied customers

Tutor for Algebra, Geometry, Statistics. Explaining math in plain English.

< Previous | Next >

Disclaimer: Information in questions, answers, and other posts on this site ("Posts") comes from individual users, not JustAnswer; JustAnswer is not responsible for Posts. Posts are for general information, are not intended to substitute for informed professional advice (medical, legal, veterinary, financial, etc.), or to establish a professional-client relationship. The site and services are provided "as is" with no warranty or representations by JustAnswer regarding the qualifications of Experts. To see what credentials have been verified by a third-party service, please click on the "Verified" symbol in some Experts' profiles. JustAnswer is not intended or designed for EMERGENCY questions which should be directed immediately by telephone or in-person to qualified professionals.

Show MoreShow Less

Ask Your Question

x