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# Solve for the predicted values of y and the residuals for the

Solve for the predicted values of y and the residuals for the following data. Comment on the size of the residuals.

Business Bankruptcies (1000) Firm Births (10,000)
34.3
58.1

35.0
55.4
38.5
57.0
40.1
58.5
35.5 57.4

37.9 58.0

Do not round the intermediate values. Round your answers to 4 decimal places, the tolerance is +/-0.0005.

x y Predicted () Residuals ()
58.1 34.3
55.4 35.0
57.0 38.5
58.5 40.1
57.4 35.5
58.0 37.9

The residual for x = 58.1 is relatively largesmall, but the residual for x = 55.4 is quite largesmall

Can the annual new orders for manufacturing in the United States be predicted by the raw steel production in the United States? Shown on the next page are the annual new orders for 10 years according to the U.S. Census Bureau and the raw steel production for the same 10 years as published by the American Iron & Steel Institute. Use these data to develop a regression model to predict annual new orders by raw steel production. Construct a scatter plot and draw the regression line through the points.

Raw Steel Production
(100,000s of net tons) New Orders
(\$ trillions)
99.9 2.74
97.9
2.87
98.9 2.93
87.9 2.87
92.9 2.98

97.9 3.09
100.6 3.36
104.9 3.61
105.3 3.75
108.6 3.95

Do not round the intermediate values. Round your answers to 5 decimal places, the tolerance is +/-0.00005.

=
Hi,

Thanks for asking me, but I was away from my computer, just came online.
Please let me know if you still need helpl with this one, or if you've other questions.

Regards
Customer: replied 6 years ago.
yes i still need help please...
Okay. Then please post the question in image format. Tables aren't quite clear. Just take the screenshot of the question, save it, then attach the image using clip icon second right of the smiley icon.

Thanks
Customer: replied 6 years ago.
I'm sorry it will not work. Ill keep trying...
Customer: replied 6 years ago.

Solve for the predicted values of y and the residuals for the following data. Comment on the size of the residuals.

 Business Bankruptcies (1000) Firm Births (10,000) 34.3 58.1 35.0 55.4 38.5 57.0 40.1 58.5 35.5 57.4 37.9 58.0

Do not round the intermediate values. Round your answers to 4 decimal places, the tolerance is +/-0.0005.

 x y Predicted ( ) Residuals () 58.1 34.3 55.4 35.0 57.0 38.5 58.5 40.1 57.4 35.5 58.0 37.9

The residual for x = 58.1 is relatively largesmall, but the residual for x = 55.

Can the annual new orders for manufacturing in the United States be predicted by the raw steel production in the United States? Shown on the next page are the annual new orders for 10 years according to the U.S. Census Bureau and the raw steel production for the same 10 years as published by the American Iron & Steel Institute. Use these data to develop a regression model to predict annual new orders by raw steel production. Construct a scatter plot and draw the regression line through the points.

 Raw Steel Production(100,000s of net tons) New Orders(\$ trillions) 99.9 2.74 97.9 2.87 98.9 2.93 87.9 2.87 92.9 2.98 97.9 3.09 100.6 3.36 104.9 3.61 105.3 3.75 108.6 3.95

Do not round the intermediate values. Round your answers to 5 decimal places, the tolerance is +/-0.00005.

=

First question

 x y Predicted ( ) Residuals () 58.1 34.3 37.4978 -3.1978 55.4 35 35.1277 -0.1277 57 38.5 36.5322 1.9678 58.5 40.1 37.8489 2.2511 57.4 35.5 36.8833 -1.3833 58 37.9 37.4100 0.4900

The residual for x = 58.1 is relatively large, but the residual for x = 55.4 is small

For second question, please post the full question.
Customer: replied 6 years ago.
Can the annual new orders for manufacturing in the United States be predicted by the raw steel production in the United States? Shown on the next page are the annual new orders for 10 years according to the U.S. Census Bureau and the raw steel production for the same 10 years as published by the American Iron & Steel Institute. Use these data to develop a regression model to predict annual new orders by raw steel production. Construct a scatter plot and draw the regression line through the points.

 Raw Steel Production(100,000s of net tons) New Orders(\$ trillions) 99.9 2.74 97.9 2.87 98.9 2.93 87.9 2.87 92.9 2.98 97.9 3.09 100.6 3.36 104.9 3.61 105.3 3.75 108.6 3.95

Do not round the intermediate values. Round your answers to 5 decimal places, the tolerance is +/-0.00005.

=
Some images didn't come through. I guess it's asking for the regression line equation.
If X occurs at the end of the equation, the equation is

Y = -2.31307 + 0.05557 X

The coefficient that goes with X is 0.05557 and the other coefficient is -2.31307