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= [(3x^2)(y^3)]^2 * (6x)^-3 divided by (9xy^3)^2
= (3x^2)^2(y^3)^2 * (6x)^-3 divided by (81x^2y^6)
two different problems
= 9x^4y^6 * 6^-3x^-3 divided by (81x^2y^6)
= 9xy^6 divided by (81x^2y^6)6^3
= 1 / 1944x
3x^2 + 12X + 32
This is not factorable.
ooo i knew it was wierd
23x^2 + 12X + 32
no, it is still not factorable.
is it x^2 + 12X + 32 ?
Then the answer is
=(x + 4)(x + 8)
23 is the question number I guess.
oo my bad 23 was problem number