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Hi,

= [(3x^2)(y^3)]^2 * (6x)^-3 divided by (9xy^3)^2

hi

oooo

= (3x^2)^2(y^3)^2 * (6x)^-3 divided by (81x^2y^6)

two different problems

= 9x^4y^6 * 6^-3x^-3 divided by (81x^2y^6)

ok ic

= 9xy^6 divided by (81x^2y^6)6^3

= 1 / 1944x

Second question.

3x^2 + 12X + 32

This is not factorable.

oh sorry,

ooo i knew it was wierd

23x^2 + 12X + 32

no, it is still not factorable.

hold on.

is it x^2 + 12X + 32 ?

Then the answer is

=(x + 4)(x + 8)

23 is the question number I guess.

oo my bad 23 was problem number

k thanks