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Scott, Here is the next one t^2 - 10t + 25 Thank

Scott, Here is the next...
Scott,

Here is the next one

t^2 - 10t + 25

Thanks,
Nena
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Answered in 2 minutes by:
6/25/2010
Scott
Scott, MIT Graduate
Category: Math Homework
Satisfied Customers: 17,710
Experience: Over 13,000 accepts & 100% feedback in the old math category
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Sure, just answers, right?

It's:

(t-5)(t-5)

 

Next, please Smile

 

-Scott

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Customer reply replied 8 years ago
factor a quadractic with leading coefficient 1

w^2 + 3w - 18

Sure, it's:

 

(w+6)(w-3)

 

-Scott

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Customer reply replied 8 years ago
just the answer,

x^2 - 8x + 12

(x-2)(x-6)

 

-Scott

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Customer reply replied 8 years ago
Multiplying rational expressions , answer lowest terms

3w/2u * 14uw/5w

Sure:

 

21w

5

 

That's a fraction with 21w on top and 5 on the bottom.

 

-Scott

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Customer reply replied 8 years ago
same as before mult. lowest terms

15w/4x * 8x/5wx

Sure,

 

6/x

 

That's a fraction with 6 on top and x on the bottom.

 

-Scott

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Customer reply replied 8 years ago
factoring difference of squares Factor

x^2 - 16

Ok:

 

(x-4)(x+4)

 

-Scott

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Customer reply replied 8 years ago
Factor the same

81z^2 - 49x^2

Sure:

 

(9z-7x)(9z+7x)

 

-Scott

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Customer reply replied 8 years ago
factoring quadratic with leading coefficient greater than 1

factor
3w^2 - 4w -4

Sure:

 

(w-2)(3w+2)

 

-Scott

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Customer reply replied 8 years ago
the same factor

3y^2 + 13y +14

Ok:

 

(y+2)(3y+7)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
quadratic trinomial and a monomial factor completely:

24u^2 - 10u^6 - 6u^5

Sure:

 

2u^2 (12 - 5u^4 - 3u^3)

 

BUT, I think you had a typo, and it should say:

24u^7 - 10u^6 - 6u^5

 

Then the answer is:

2u^5 (4u-3)(3u+1)

 

-Scott

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Customer reply replied 8 years ago
you were right, so sorry, it has been a bad day at the office.

the same as above:

10z^5 + 35z^4 - 20z^3

No problem!

 

 

5z^3 ( 2z-1 )( z+4 )

 

-Scott

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Customer reply replied 8 years ago
Scott,
After this one I after to stop for about a hour and fix some supper for my mother that is 84, and then I will be right back.Is that ok with you.

completeing the square--find the value of k such that x^2 - 14x + k is a perfect square

I shant be long.
can we leave this open like this or do I need to close it out.
Nena

Yes, that sounds great -- I need to get dinner, too Smile Just come right back to this thread and we can keep going. No need to close it out.

 

The answer is:

49

 

Talk to you in about an hour.

-Scott

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Customer reply replied 8 years ago
Scott,
I'm back--

Find the value of a such that

x^2 -18x + a

is a perfect square
when ever you get ready, you are an angle.

Ok, sure!

 

81

 

-Scott

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Customer reply replied 8 years ago
value of a perfect square

u^2 + 6u + a

Ok:

 

9

 

-Scott

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Customer reply replied 8 years ago
quadratic polynomial in two variables Factor:

4x^2 + 3xy -10y^2

Ok:

 

( 4x-5y )( x+2y )

 

-Scott

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Customer reply replied 8 years ago
factor the same

2x^2 + 3xy - 14y^2

Sure!

 

( x-2y )( 2x+7y )

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
Scott,

It is comming a very bad storm here and I need to shut down for a while I will check back in a just a little bit if that is ok. I need to finishe this if I can. Can I check back in here with you where I left off.

Thanks,
Nena

Ok, that's fine!

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
Scott,
Just one of those Southern evening rain storms,

factor

2x^2 + 17xy + 30y^2

No problem!

 

( 2x+5y )( x+6y )

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
find the greatest common factor of the two expressions simplify answer:

22u^4 w^6 y^8 and 6uy^8

Sure:

 

2 u y^8

 

-Scott

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Customer reply replied 8 years ago
same as before

6u^7z^8 and 3u^4x^7z^5

Sure, the GCF.

 

3 u^4 z^5

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
difference of squares formula factor completely

48x^3 - 3x^3 y^4

Ok:

 

3x^3 (4 + y^2)(2 + y)(2 - y)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
Factor completely

w^4 y^3 - y^3

Ok:

 

y^3 (w^2 + 1)(w+1)(w-1)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
find least common multiple of the two expression then simplify

2u^4 y^9 and t^5 u^7 y^8

Ok:

 

2 u^7 y^9 t^5

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
same as before

14xz^9 and 4u^3 x^3 z

Ok:

 

28 x^3 z^9 u^3

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
multivariate polynomial by grouping factor

xw - 7t + 7x - wt

I think there is only one or two more

Sure!

 

(w+7)(x-t)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
same:

tx - 3x - 3w + wt

Ok:

 

(t-3)(x+w)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
multivariate polynomial grouping problem type 2

factor

-2t - 18y + 9y^2 + yt

Ok:

 

(y-2)(t+9y)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
same

-30y -yt + 5t + 6y^2

Sure!

 

(5-y)(t-6y)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
factor the sum or difference of two cubes factor completely:

27 - 8t^3

Ok:

 

(3-2t) (9 + 6t + 4t^2)

 

-Scott

Ask Your Own Math Homework Question
Customer reply replied 8 years ago
same

x^3 + 1

Sure:

 

(x+1) (x^2 - x + 1)

 

-Scott

Scott
Scott, MIT Graduate
Category: Math Homework
Satisfied Customers: 17,710
Experience: Over 13,000 accepts & 100% feedback in the old math category
Verified
Scott and 87 other Math Homework Specialists are ready to help you
Ask your own question now
Customer reply replied 8 years ago
Thanks you have saved my life and my math grade.

I will put a bonus in and hope you will help me out next week with the same thing, if you are not busy that is. I will ask for you by name.

Thanks
Nena

Thanks! Sure!

-Scott

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Disclaimer: Information in questions, answers, and other posts on this site ("Posts") comes from individual users, not JustAnswer; JustAnswer is not responsible for Posts. Posts are for general information, are not intended to substitute for informed professional advice (medical, legal, veterinary, financial, etc.), or to establish a professional-client relationship. The site and services are provided "as is" with no warranty or representations by JustAnswer regarding the qualifications of Experts. To see what credentials have been verified by a third-party service, please click on the "Verified" symbol in some Experts' profiles. JustAnswer is not intended or designed for EMERGENCY questions which should be directed immediately by telephone or in-person to qualified professionals.

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