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This question is for Ryan:

Need to see if you can help me out with these two question: 1. Work efficiency. In a study of worker efficiency at Wong Laboratories it was found that the number of components assembled per hour by the average worker t hours after starting work could be modeled by the formula N(t) = -3t^3 + 23t^2 + 8t.

a) Rewrite the formula by factoring the right-hand side completely.

b)Use the factored version of the formula to find N(3).

c) Use the accompanying graph to estimate the time at which the workers are most efficient.

2. Decreasing cube. Each of the three dimensions of a cube with sides of length s centimeters is decreased by a whole number of centimeters. The new volume in cubic

centimeters is given by V(s)=s^3 - 13s^2 + 54s - 72.

a) Find V(10).

b) If the new width is s-6 centimeters, then what are the new length and height?

c) Find the volume when s+10 by multiplying the length, width, and height.

Please let me know if you can do this for me I will need this by Friday afternoon EST.

Thanks

Nena

Need to see if you can help me out with these two question: 1. Work efficiency. In a study of worker efficiency at Wong Laboratories it was found that the number of components assembled per hour by the average worker t hours after starting work could be modeled by the formula N(t) = -3t^3 + 23t^2 + 8t.

a) Rewrite the formula by factoring the right-hand side completely.

b)Use the factored version of the formula to find N(3).

c) Use the accompanying graph to estimate the time at which the workers are most efficient.

2. Decreasing cube. Each of the three dimensions of a cube with sides of length s centimeters is decreased by a whole number of centimeters. The new volume in cubic

centimeters is given by V(s)=s^3 - 13s^2 + 54s - 72.

a) Find V(10).

b) If the new width is s-6 centimeters, then what are the new length and height?

c) Find the volume when s+10 by multiplying the length, width, and height.

Please let me know if you can do this for me I will need this by Friday afternoon EST.

Thanks

Nena

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Disclaimer: Information in questions, answers, and other posts on this site ("Posts") comes from individual users, not JustAnswer; JustAnswer is not responsible for Posts. Posts are for general information, are not intended to substitute for informed professional advice (medical, legal, veterinary, financial, etc.), or to establish a professional-client relationship. The site and services are provided "as is" with no warranty or representations by JustAnswer regarding the qualifications of Experts. To see what credentials have been verified by a third-party service, please click on the "Verified" symbol in some Experts' profiles. JustAnswer is not intended or designed for EMERGENCY questions which should be directed immediately by telephone or in-person to qualified professionals.