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Given the question below The length...

Given the question below

The length of time to do a complete full service oil change at Speedy-Lube is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

X P(X x) Mean Std dev

11 .0146 .9854 15.8 2.2

15 .3581 .6419 15.8 2.2

21 .9910 .0090 15.8 2.2

24 .9999 .0001 15.8 2.2

p(lower) p(upper)

(A) Analyze the output above to determine what percentage of complete full service oil changes will fall between 15 and 21 minutes.

(B) What percentage of complete full service oil changes will take less than 11 minutes?

If 1000 cars had a complete full service oil change, how many would you expect to be finished in less than 11 minutes?

The length of time to do a complete full service oil change at Speedy-Lube is normally distributed with a mean of 15.8 minutes and a standard deviation of 2.2 minutes

X P(X x) Mean Std dev

11 .0146 .9854 15.8 2.2

15 .3581 .6419 15.8 2.2

21 .9910 .0090 15.8 2.2

24 .9999 .0001 15.8 2.2

p(lower) p(upper)

(A) Analyze the output above to determine what percentage of complete full service oil changes will fall between 15 and 21 minutes.

(B) What percentage of complete full service oil changes will take less than 11 minutes?

If 1000 cars had a complete full service oil change, how many would you expect to be finished in less than 11 minutes?

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