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# Young�s double slit experiment is performed with 589 nm

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light and a distance of...
Young�s double slit experiment is performed with 589 nm light and a distance of 2.00 m between the slits and the screen. The tenth interference minimum is observed 7.26 mm from the central maximum. Determine the spacing of the slits.
Submitted: 8 months ago.Category: Homework
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8/3/2017
Tutor: akch2002, Engineer replied 8 months ago
akch2002, Engineer
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I can solve this problem. Kindly inform when it is due.

Customer reply replied 8 months ago
now
Tutor: akch2002, Engineer replied 8 months ago

How many hrs from now?

Customer reply replied 8 months ago
It is too much i can pay \$20 if it is well done.
Tutor: akch2002, Engineer replied 8 months ago

You can re-price it but inform how many hrs from now.

Customer reply replied 8 months ago
3hrs if you can not do it let me know right now. So I can do it myself now.
Tutor: akch2002, Engineer replied 8 months ago

ok, I will do it.

Customer reply replied 8 months ago
\$20
Customer reply replied 8 months ago
resubmit it for \$20
Customer reply replied 8 months ago
are we good to go?
Tutor: akch2002, Engineer replied 8 months ago

Yes; I will go ahead. You can ask for refund of \$10.

Customer reply replied 8 months ago
I'm waiting for the response in 2 and half hour
Tutor: akch2002, Engineer replied 8 months ago

I will try to reply much earlier.

Tutor: akch2002, Engineer replied 8 months ago

ans. is given in the attached file.

Customer reply replied 8 months ago
I have question if m=0,1,2....9 then the tenth isnt 9? from 0?
Tutor: akch2002, Engineer replied 8 months ago

yes, we will have d = 9*589*10^-9*2/(7.26*10^-3)=1.46mm

Tutor: akch2002, Engineer replied 8 months ago

Don't you think that n=0 for central line; n=1 for 1st line and so on. Hence, n =10 should be for 10th line.

Customer reply replied 8 months ago
ok I got it
Customer reply replied 8 months ago
is it done all? did you see the attachment? it is 6 exercices
Tutor: akch2002, Engineer replied 8 months ago
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