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Since molarity = number of moles / liters of solution, thenlet x be the number of moles of KCl0.9 M = x / 3.5L, then x = 0.9 (3.5) = 3.15 molesSince the molar mass of KCl is 74.5513g/mol, then 3.15 moles of KCl is = 3.15mol (74.5513g/mol) =###-##-####gmsso dissolved###-##-####gms of KCl into 3.5 Liters of solution in order to produce 0.9M of solution of KCL.
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