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A 0.11 kg bullet traveling at 589 m/s hits a 3.8 kg block of…

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A 0.11 kg bullet traveling...
A 0.11 kg bullet traveling at 589 m/s hits a 3.8 kg block of wood and stays in the wood. What is the velocity (speed)of the wood block immediately after the bullet hits it?
Submitted: 3 years ago.Category: Homework
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6/28/2015
Tutor: Lane, JD, MBA, CFP, CRPS replied 3 years ago
Lane
Lane, JD, MBA, CFP, CRPS
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Hi,Applying the law of conservation of momentum, we get ....M1V1 + M2V2 = M3V3.0.11 * 589 + 0 = (3.8 + 0.11) * V.3.91 V = 64.79.V = 16.57 m/s
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