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In an acid-base titration, 24.88 mL of an NaOH solution are

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In an acid-base titration, 24.88 mL of an NaOH solution are needed to neutralize 26.43 mL of a 0.1049 M HCl solution. To find the molarity of the NaOH solution, we can use the following procedure:

a. Note the value of M H- in the HCl solution:

b. Find M OH- in the NaOH solution.

c. Obtain M NaOH from M OH-

Note: The H- in part a, the OH- in part b, and the NaOH & OH- in part c are all subscripts.
Submitted: 5 years ago.
Category: Homework
Expert:  Homework Girl replied 5 years ago.
Does M stand for Moles or Molarity? It seems like it stands for Moles in part a and b (since Molarity of HCl is given ) and Molarity in part C.
Expert:  Homework Girl replied 5 years ago.

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