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# I am looking for someone that is good in statistics to do four

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I am looking for someone that is good in statistics to do four math problems.
Hi,

I'd love to help. Let me know what questions do you have.

Regards
Customer: replied 5 years ago.
Here is the answer to #1
1)
I) a) z = (0.5 - 5.2)/3.8 = -1.237
So, z-interval is z ≤ -1.237

b) For x=-2, z = (-2 - 5.2)/3.8 = -1.895
For x=2.9, z = (2.9 - 5.2)/3.8 = -0.605
So, z-interval is -1.895 ≤ z ≤ -0.605

II) d) For z=2.8, x=5.2+2.8*3.8 = 15.84
So, x-interval is x ≥15.84

e) for z = -1, x = 5.2-1*3.8 = 1.4
For z=2.5, x = 5.2+2.5*3.8 = 14.7
So, x-interval is 1.4 ≤ x ≤ 14.7

III) 1) 0.01
2) 0.98

IV) 2.53

Please click Accept.
I'll post solution to next part asap.

Regards
R.R. Jha and 2 other Homework Specialists are ready to help you
Here is answer to #2

a) For x=1 hour, z = (1-2)/0.3 = -3.3333
For x=3 hour, z = (3-2)/0.3 = 3.3333

So, probability that drug would be effective for 1 to 3 hours is

P(1 ≤ x ≤ 3)
= P( -3.3333 ≤ z ≤ 3.3333)
= P(z ≤ 3.3333) - P(z ≤ -3.3333)
= 0.9996 - 0.0004
= 0.9992

Regards
R.R. Jha and 2 other Homework Specialists are ready to help you
Here is #3

a) Given µ = 390 and σ = 65,
For x=450, z = (450 - 390)/65 = 0.9231

So, probability that an individual male African tiger would weight more than 450 lb. is

P(x > 450)
= 1 - P(x ≤ 450)
= 1 - P(z ≤ 0.9231)
= 1 - 0.822
= 0.178

Regards
R.R. Jha and 2 other Homework Specialists are ready to help you
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R.R. Jha and 2 other Homework Specialists are ready to help you