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# 3 to the square root of y-1 - the square root of 8y-1 equals

### Resolved Question:

3 to the square root of y-1 - the square root of 8y-1 equals zero
Submitted: 7 years ago.
Category: Homework
Expert:  abozer replied 7 years ago.
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abozer :

Hi,

abozer :

is it cubic root or 3 times the square root?

JACUSTOMER-jkm6dfov- :

no it is the number 3

abozer :

Is it the following?

abozer :
JACUSTOMER-jkm6dfov- :

no that is not correct it is the number three in front of the square root

abozer :

or the following?

abozer :
JACUSTOMER-jkm6dfov- :

that is correct

abozer :

ok.

abozer :

3sqrt(y - 1) - sqrt(8y - 1) = 0

abozer :

3sqrt(y - 1) = sqrt(8y - 1)

abozer :

9(y - 1) = (8y - 1)

abozer :

9y - 9 = 8y - 1

abozer :

y = 8

abozer :

Let me know if you have any questions.

JACUSTOMER-jkm6dfov- :

ok how about the square root of 3x-6 plus the square root of 2x+6 plus 1 equals zero

JACUSTOMER-jkm6dfov- :

I keep getting a no solution on this one

abozer :

ok. let's solve it.

abozer :

sqrt(3x - 6) + sqrt(2x + 6) + 1 = 0

abozer :

There is no solution.

abozer :

Because square root cannot be negative

JACUSTOMER-jkm6dfov- :

I thought so too and my computer program I solve it on tells me there is

abozer :

the solution is not real number.

JACUSTOMER-jkm6dfov- :

thank you once again I greatly appreciate it