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The drawing shows two graphs that represent a transverse wave

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The drawing shows two graphs that represent a transverse wave on a string. The wave is moving in the +x direction. Using the information contained in these graphs, write the mathematical expression (similar to Equation 16.3(wave moving in positive X direction: y=Asin(2pift-2pix/wavelength) or 16.4 wave moving in negative x direction(y=Asin(2pift+2pix/wavelength)) for the wave. (Answer in terms of t and x. Assume standard units.) http://www.mediafire.com/?sharekey=01781d94085999f0d2db6fb9a8902bda

Since the wave is moving in the +x direction, it is of the form y = A sin(2 pi f t - 2 pi x/wavelength)

From both graphs, the amplitude of the wave, which is the distance from the center to the peak, is A = 0.01m.

From the first graph, since it is a graph with respect to distance, the wavelength of the wave is 0.04m. From the second graph, since it is a graph with respect to time, the period of the wave is T=0.2s. The frequency f is one over the period, so f = 1/(0.2s) = 5 Hz.

Therefore, the equation is y = 0.01m sin[2 pi (5 Hz) t - 2 pi x / (0.04m)], or if you leave out the units and always express x in meters and t in seconds, y = 0.01 sin[10 pi t - 50 pi x]