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Martin, Engineer
Category: General
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# length of rectangle is 3cm longer than twice the width and

### Resolved Question:

length of rectangle is 3cm longer than twice the width and that the perimeter of the rectangle is 90cm.
a) equation for perimeter involving only W, the width of the rectangle
b)solve the linear equation algebraically to find the width of the rectangle, find the length also
c)using same length as answer in part b, find new perimeter if new width is 5 less than one-half of the length
Submitted: 6 years ago.
Category: General
Expert:  Martin replied 6 years ago.
Hello, welcome to just answer.

equation 1: L=3+2W
equation 2: 90=2L+2W

a)
If we replace L in equation 2 by L in equation 1 we get:
90=2(3+2W)+2W

b)
Solving 90=2(3+2W)+2W for W we get:
90=6+4W+2W
90=6+6W
84=6W
84/6=W = 14 = width

To then find L we use equation 2 (90=2L+2W)
90=2L+2*14
90=2L+28
(90-28)/2) = 31 = length

so perimeter = 14 + 14 + 31 +31 = 90

c)
L = 31 again.
NEW_W = (31/2)-5 = 10.5

New perimeter = 10.5 + 10.5 + 31 + 31 = 83

Customer: replied 6 years ago.
If my understanding is correct from your response I forgot to include the 3 for the 3cm in my equation?
Customer: replied 6 years ago.
Relist: Other.
unsure, no answer to reply still confused
Expert:  Martin replied 6 years ago.
Sorry for the delay.

"length of rectangle is 3cm longer than twice the width"

So, yes you need to use the 3cm information. I did not saw your own calculation so i can't really point where you messed up.

The equation 1 and equation 2 i wrote in my original answer are the original data of the problem wrote as equation instead of text.
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