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Martin, Engineer
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A 0.058 kg aluminum bullet traveling at 489 m/s strikes an

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A 0.058 kg aluminum bullet traveling at 489 m/s strikes an armor plate and comes to a stop. If all its energy is converted to heat that is absorbed by the bullet, what is the bullet's temperature change in degrees Celsius?
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We first need to find the kinetic energy in the bullet just before the impact.

Q = (1/2)*mvˆ2 = 0.5 * 0.058 * 489ˆ2 = 6934.5 Joule

Specific heat (c) of aluminum is 900 J(Kg*degree_Celcius)

The temperature delta = Q/(mc) = 6934/(0.058*900) = 132.84 Celcius.
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