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population mean using the data...

Construct a 99% confidence interval to estimate the population mean using the data below.

x=23

s=4.5

n=20

N=180

The 99% confidence interval for the population mean is ,.

(Round to two decimal places as needed.)Construct a 90% confidence interval to estimate the population proportion with a sample proportion equal to 0.50 and a sample size equal to 200.

LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table.

A 90% confidence interval estimates that the population proportion is between a lower limit of nothing and an upper limit of nothing.

(Round to three decimal places as needed.)A cell phone company would like to estimate the average number of text messages received by American teenagers per month. A random sample of 50 teenaged customers was selected. The sample average was 2,226 messages per month, and the sample standard deviation was 958 messages per month. Construct confidence intervals with the given confidence levels.

a.

90%

b.

95%

c.

99%

a. The 90% confidence interval has a lower limit of nothing and an upper limit of nothing.

(Type integers or decimals rounded to one decimal place as needed.)

b. The 95% confidence interval has a lower limit of nothing and an upper limit of nothing.

(Type integers or decimals rounded to one decimal place as needed.)

c. The 99% confidence interval has a lower limit of nothing and an upper limit of nothing.

(Type integers or decimals rounded to one decimal place as needed.)A governmental department would like to estimate the average weekly wages for adults with a margin of error equal to $16. Determine the sample sizes needed to construct a confidence interval for this estimate using the following confidence levels. Assume the population standard deviation for the weekly wage is $140.

a. 90%

b. 98%

c. 99%

d. Explain why the confidence level affects the sample size needed to obtain a particular margin of error.

a. The sample size needed is nothing.

(Round up to the nearest integer.)

b. The new sample size needed would be nothing.

(Round up to the nearest integer.)

c. The new sample size needed would be nothing.

(Round up to the nearest integer.)

d. To be more confident that the interval contains the true population parameter given a constant margin of error, a

▼

larger

smaller

sample size would be needed, since the value of

▼

ME Subscript pMEp

z Subscript alpha divided by 2zα/2

sigmaσ

will

▼

increase

decrease

as the confidence level increases.

x=23

s=4.5

n=20

N=180

The 99% confidence interval for the population mean is ,.

(Round to two decimal places as needed.)Construct a 90% confidence interval to estimate the population proportion with a sample proportion equal to 0.50 and a sample size equal to 200.

LOADING... Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table.

A 90% confidence interval estimates that the population proportion is between a lower limit of nothing and an upper limit of nothing.

(Round to three decimal places as needed.)A cell phone company would like to estimate the average number of text messages received by American teenagers per month. A random sample of 50 teenaged customers was selected. The sample average was 2,226 messages per month, and the sample standard deviation was 958 messages per month. Construct confidence intervals with the given confidence levels.

a.

90%

b.

95%

c.

99%

a. The 90% confidence interval has a lower limit of nothing and an upper limit of nothing.

(Type integers or decimals rounded to one decimal place as needed.)

b. The 95% confidence interval has a lower limit of nothing and an upper limit of nothing.

(Type integers or decimals rounded to one decimal place as needed.)

c. The 99% confidence interval has a lower limit of nothing and an upper limit of nothing.

(Type integers or decimals rounded to one decimal place as needed.)A governmental department would like to estimate the average weekly wages for adults with a margin of error equal to $16. Determine the sample sizes needed to construct a confidence interval for this estimate using the following confidence levels. Assume the population standard deviation for the weekly wage is $140.

a. 90%

b. 98%

c. 99%

d. Explain why the confidence level affects the sample size needed to obtain a particular margin of error.

a. The sample size needed is nothing.

(Round up to the nearest integer.)

b. The new sample size needed would be nothing.

(Round up to the nearest integer.)

c. The new sample size needed would be nothing.

(Round up to the nearest integer.)

d. To be more confident that the interval contains the true population parameter given a constant margin of error, a

▼

larger

smaller

sample size would be needed, since the value of

▼

ME Subscript pMEp

z Subscript alpha divided by 2zα/2

sigmaσ

will

▼

increase

decrease

as the confidence level increases.

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