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Ryan
Ryan, Engineer
Category: Calculus and Above
Satisfied Customers: 9023
Experience:  B.S. in Civil Engineering
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Just wondering if I can have your time Saturday EST around

This answer was rated:

Hey just wondering if I can have your time Saturday EST around 2pm for calculus questions and also receive help with calculus homework. Which I can send you before Saturday so it isnt all last minute

Hi,

Thank you for using the site, and thank you for requesting me.

Yes, I can be available at that time.

Ryan

Customer: replied 8 months ago.
Awesome thank you. I will go ahead and start sending you screenshots and you can work on them whenever

Ok, sounds good.

Customer: replied 8 months ago.
Customer: replied 8 months ago.

Thanks. I have seven image files for the first set.

Hi,

Here are the solutions for the first set:

CalculusSolutions

As always, please let me know if there are issues with any of these solutions.

Thanks,

Ryan

Customer: replied 8 months ago.
1 and #3; both of the middle portions are wrong and #14 and #15 are wrong

Could you please send screenshots of what was entered?

For #1 and #3, there are different ways of entering what amounts to the same thing, so it's difficult to know what they expect.

For #14 and #15, there shouldn't be any issue with those as the problems were straightforward. I suspect that there is likely to be a typo issue there, so seeing what was entered might help.

Thanks,

Ryan

Customer: replied 8 months ago.

Thanks.

For #1, change both from "1/5 + 1" to "6/5".

For #3, change both from "-6/5 + 1" to "-1/5".

For #14 and #15, add absolute value bars around the "x" in the natural logarithm terms.

Customer: replied 8 months ago.
Thank you:)

You're welcome.

Customer: replied 8 months ago.
Customer: replied 8 months ago.
Customer: replied 8 months ago.
End of second set. Dont worry about the graphs I will do those

Ok, got them.

Here are the solutions for the problems that were included in the images:

Solutions2

Note that problem #12 was not included in the screenshots, and problem #18 was cut off with no problem information shown.

Thanks,

Ryan

Customer: replied 8 months ago.
Hey, is there anyway you can be ready in an hour? at 1

Yes.

Customer: replied 8 months ago.
okay awesome, I wont be able to send you screenshots itll be over my phone so ill have to text the problems out as best as I can on the problems I can do it on

ok

Customer: replied 8 months ago.
F (x)=x^2-x-12
Customer: replied 8 months ago.
Find the equation of the servant line joining points through (-2,-6) (4,0)

Are those two separate problems?

Customer: replied 8 months ago.
B-use the mean value theorem to determine c in interval (-2,4) so that tangent line c is parallel at secant line. Find equation of tangent line through c
Customer: replied 8 months ago.
No all 1 problem

Equation of the secant line through (-2, -6) and (4, 0) is y = x - 4.

The point c is (1, -12)

The equation of the tangent line through (1, -12), parallel to the secant line, is y = x - 13

Customer: replied 8 months ago.
Find the absolute extrema of the function on the closed interval
F (x)=x^3-3/2 x^2 , [-1,4]

Absolute minimum is -5/2

Absolute maximum is 40

Customer: replied 8 months ago.
The ordering and transportation cost C for components used in a manufacturing process is approximated by the function where c is measured in dollars and x is the order size in hundreds
C (x)=12(1/x + x/x+3)
Verify that c(6)=c (3)

C(6) = 12(1/6 + 6/9) = 12(5/6) = 10

C(3) = 12(1/3 + 3/6) = 12(5/6) = 10

Customer: replied 8 months ago.
B - find the order size through interval (3,6)
Customer: replied 8 months ago.
F (x)=(x+7)^2/3
Critical
Increasing
Decreasing
Maximum
Minimum

Order size for minimum cost is 3/2 + (3√3)/2, or ≈ 4.098 (hundreds)

Customer: replied 8 months ago.
Find the length and width of the rectangle with a maximum area that has a perimeter of 7P units
Smaller value=
Larger value=

For F (x)=(x+7)^2/3:

Critical point at x = -7

Increasing on (-7, ∞)

Decreasing on (-∞, 7)

Maximum: No maximum

Minimum: 0

Rectangle with perimeter 7P:

Smaller value = 7P/4

Larger value = 7P/4

(The rectangle of "maximum area" is a square.)

Customer: replied 8 months ago.
Y=x/x^2+25
Intercept
Relative minimum
Relative maximum
Points of inflection
Equation of asymptotes
Customer: replied 8 months ago.
F (x)=x^5-5x
Intercepts (there are 3 answer boxes)
Relative minimum
Relative maximum
Points of inflection
Equation of asymptotes

For Y=x/x^2+25:

Intercept = (0, 0)

Rel. Min. = -1/10, at x = -5

Rel. Max. = 1/10, at x = 5

Points of inflection = -5√3, 0, 5√3

Equation of asymptote: y = 0

Customer: replied 8 months ago.
A rectangular package to be sent by a postal service can have a max combined length and girth of 72 inches. Find the dimensions of the package of max volume that can be sent
X=
Y=

F (x)=x^5-5x

Intercepts (there are 3 answer boxes): -4th root of 5, 0, +4th root of 5

Relative minimum: -4 at x = 1

Relative maximum: +4 at x = -1

Points of inflection: (0, 0)

Equation of asymptotes: No asymptotes

For the one about the package, what are X and Y? Is the end of the package square?

Customer: replied 8 months ago.
Sorry there is a figure but i can't show you but it doesn't have any numbers on it

Ok. Is X the dimension of the square end, and Y the length?

Customer: replied 8 months ago.

If that is the case, then X = 12 inches and Y = 24 inches

Customer: replied 8 months ago.
What were the minimum and maximum of the last question

For F (x)=x^5-5x?

The relative minimum is -4, and the relative maximum is 4.

Those are also the absolute minimum and maximum.

Customer: replied 8 months ago.
G (x)=x^2-2x-360
Critical numbers
This is a step by step question

Critical value: x = 1

Customer: replied 8 months ago.
First consider the interval (-infinity,1) let x=0
It wants us to fill in the blanks
G (x)=2 (x-1)
G (0)=2 ( -1)
G (0)=2 ( )
G (0)=
Customer: replied 8 months ago.
Sorry the first two equations there are spaces in the front inside the parentheses

G (x)=2 (x-1)
G (0)=2 (0 -1)
G (0)=2 (-1 )
G (0)=-2

Customer: replied 8 months ago.
Since g (0) (greater or less? ) 0, the function is (decreasing or increasing?) In the interval (-infinity, 1)

Less

decreasing

Customer: replied 8 months ago.
Now consider the inteval (1,infinity) let x=2
G (x)=2 (x-1)
This is the same as the last (3 answers) just with 2

G (x)=2 (x-1)
G (2)=2 (2 -1)
G (2)=2 (1 )
G (2)=2

greater than

increasing

Customer: replied 8 months ago.
New problem. Step by step
Y=x^7-7x
Find the three intercepts
Customer: replied 8 months ago.
I know you'll need the points of inflection
Asymptotes
And relative extrema

Intercepts: -6th root of 7, 0, +6th root of 7

No asymptotes

Relative minimum: -6

Relative maximum: +6

Customer: replied 8 months ago.
Inflection points

Inflection point is (0, 0)

Customer: replied 8 months ago.
Y=7x^6-7
Differentiate y with respect to x
Part2
So y=0 when. X=?

y'(x) = 42x^5

Is the second part really asking when "y" is equal to 0, or is is "y-prime"?

Customer: replied 8 months ago.
One more and I have a screenshot for ya
Customer: replied 8 months ago.
oh nevermind, you already did that one it just cleared my answer

Ok, great. I wasn't sure what they wanted for "c" there. It could have been just the x-coordinate, or it could have been the (x, y) ordered pair.

Customer: replied 8 months ago.
Customer: replied 8 months ago.

I have the first 8 screenshots for Set 3. Please let me know if there are more, and when the deadline is for completion.

Hi again,

Could you please post a screenshot of "Example 1"? It is referred to in problem #1, and I'm concerned that the "correct" answer might be slightly different than just calculating the straight integral.

Thanks,

Ryan

Customer: replied 8 months ago.
I am so sorry. Got slammed with work and the deadline is tonight but I am gonna ask for an extension
Customer: replied 8 months ago.
Here is the last of the second set; I guess I forgot to include them or they didnt send :( my apologies
Customer: replied 8 months ago.
4th set- If you cant finish by tonight it isnt a big deal. My professor lets us go back and complete them at the end of the semester and ive never asked for an extension before so Im sure he wont care with the holidays being so close

Here are the remaining solutions:

CalcSolutions

Please let me know if there are any issues.

Thanks,

Ryan

Customer: replied 8 months ago.
Hey im sorry i havent responded been a busy week. And my teacher hasnt responded about extending so I havent been able to get you the last set..

Ok, thanks for the update.

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