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Just wondering if I can have your time Saturday EST around

Hey just wondering if I...
Hey just wondering if I can have your time Saturday EST around 2pm for calculus questions and also receive help with calculus homework. Which I can send you before Saturday so it isnt all last minute
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Answered in 2 minutes by:
11/18/2016
Ryan
Ryan, Engineer
Category: Calculus and Above
Satisfied Customers: 9,116
Experience: B.S. in Civil Engineering
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Hi,

Thank you for using the site, and thank you for requesting me.

Yes, I can be available at that time.

Ryan

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Customer reply replied 1 year ago
Awesome thank you. I will go ahead and start sending you screenshots and you can work on them whenever

Ok, sounds good.

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Customer reply replied 1 year ago
First Set
Screenshot (371).pngScreens...pngScreenshot (372).pngScreens...pngScreenshot (373).pngScreens...pngScreenshot (374).pngScreens...png

Thanks. I have seven image files for the first set.

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Hi,

Here are the solutions for the first set:

CalculusSolutions

As always, please let me know if there are issues with any of these solutions.

Thanks,

Ryan

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Customer reply replied 1 year ago
1 and #3; both of the middle portions are wrong and #14 and #15 are wrong

Could you please send screenshots of what was entered?

For #1 and #3, there are different ways of entering what amounts to the same thing, so it's difficult to know what they expect.

For #14 and #15, there shouldn't be any issue with those as the problems were straightforward. I suspect that there is likely to be a typo issue there, so seeing what was entered might help.

Thanks,

Ryan

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Thanks.

For #1, change both from "1/5 + 1" to "6/5".

For #3, change both from "-6/5 + 1" to "-1/5".

For #14 and #15, add absolute value bars around the "x" in the natural logarithm terms.

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Customer reply replied 1 year ago
Thank you:)

You're welcome.

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Customer reply replied 1 year ago
Second Set
Screenshot (381).pngScreens...pngScreenshot (382).pngScreens...pngScreenshot (383).pngScreens...pngScreenshot (384).pngScreens...png
Customer reply replied 1 year ago
End of second set. Dont worry about the graphs I will do those
Screenshot (388).pngScreens...pngScreenshot (389).pngScreens...pngScreenshot (390).pngScreens...pngScreenshot (391).pngScreens...png

Ok, got them.

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Here are the solutions for the problems that were included in the images:

Solutions2

Note that problem #12 was not included in the screenshots, and problem #18 was cut off with no problem information shown.

Thanks,

Ryan

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Customer reply replied 1 year ago
Hey, is there anyway you can be ready in an hour? at 1

Yes.

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Customer reply replied 1 year ago
okay awesome, I wont be able to send you screenshots itll be over my phone so ill have to text the problems out as best as I can on the problems I can do it on

ok

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Customer reply replied 1 year ago
F (x)=x^2-x-12
Customer reply replied 1 year ago
Find the equation of the servant line joining points through (-2,-6) (4,0)

Are those two separate problems?

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Customer reply replied 1 year ago
B-use the mean value theorem to determine c in interval (-2,4) so that tangent line c is parallel at secant line. Find equation of tangent line through c
Customer reply replied 1 year ago
No all 1 problem

Equation of the secant line through (-2, -6) and (4, 0) is y = x - 4.

The point c is (1, -12)

The equation of the tangent line through (1, -12), parallel to the secant line, is y = x - 13

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Customer reply replied 1 year ago
Find the absolute extrema of the function on the closed interval
F (x)=x^3-3/2 x^2 , [-1,4]

Absolute minimum is -5/2

Absolute maximum is 40

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Customer reply replied 1 year ago
The ordering and transportation cost C for components used in a manufacturing process is approximated by the function where c is measured in dollars and x is the order size in hundreds
C (x)=12(1/x + x/x+3)
Verify that c(6)=c (3)

C(6) = 12(1/6 + 6/9) = 12(5/6) = 10

C(3) = 12(1/3 + 3/6) = 12(5/6) = 10

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Customer reply replied 1 year ago
B - find the order size through interval (3,6)
Customer reply replied 1 year ago
F (x)=(x+7)^2/3
Critical
Increasing
Decreasing
Maximum
Minimum

Order size for minimum cost is 3/2 + (3√3)/2, or ≈ 4.098 (hundreds)

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Customer reply replied 1 year ago
Find the length and width of the rectangle with a maximum area that has a perimeter of 7P units
Smaller value=
Larger value=

For F (x)=(x+7)^2/3:

Critical point at x = -7

Increasing on (-7, ∞)

Decreasing on (-∞, 7)

Maximum: No maximum

Minimum: 0

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Rectangle with perimeter 7P:

Smaller value = 7P/4

Larger value = 7P/4

(The rectangle of "maximum area" is a square.)

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Customer reply replied 1 year ago
Y=x/x^2+25
Intercept
Relative minimum
Relative maximum
Points of inflection
Equation of asymptotes
Customer reply replied 1 year ago
F (x)=x^5-5x
Intercepts (there are 3 answer boxes)
Relative minimum
Relative maximum
Points of inflection
Equation of asymptotes

For Y=x/x^2+25:

Intercept = (0, 0)

Rel. Min. = -1/10, at x = -5

Rel. Max. = 1/10, at x = 5

Points of inflection = -5√3, 0, 5√3

Equation of asymptote: y = 0

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Customer reply replied 1 year ago
A rectangular package to be sent by a postal service can have a max combined length and girth of 72 inches. Find the dimensions of the package of max volume that can be sent
X=
Y=

F (x)=x^5-5x

Intercepts (there are 3 answer boxes): -4th root of 5, 0, +4th root of 5

Relative minimum: -4 at x = 1

Relative maximum: +4 at x = -1

Points of inflection: (0, 0)

Equation of asymptotes: No asymptotes

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For the one about the package, what are X and Y? Is the end of the package square?

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Customer reply replied 1 year ago
Sorry there is a figure but i can't show you but it doesn't have any numbers on it

Ok. Is X the dimension of the square end, and Y the length?

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If that is the case, then X = 12 inches and Y = 24 inches

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Customer reply replied 1 year ago
What were the minimum and maximum of the last question

For F (x)=x^5-5x?

The relative minimum is -4, and the relative maximum is 4.

Those are also the absolute minimum and maximum.

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Customer reply replied 1 year ago
G (x)=x^2-2x-360
Critical numbers
This is a step by step question

Critical value: x = 1

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Customer reply replied 1 year ago
First consider the interval (-infinity,1) let x=0
It wants us to fill in the blanks
G (x)=2 (x-1)
G (0)=2 ( -1)
G (0)=2 ( )
G (0)=
Customer reply replied 1 year ago
Sorry the first two equations there are spaces in the front inside the parentheses

G (x)=2 (x-1)
G (0)=2 (0 -1)
G (0)=2 (-1 )
G (0)=-2

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Customer reply replied 1 year ago
Since g (0) (greater or less? ) 0, the function is (decreasing or increasing?) In the interval (-infinity, 1)

Less

decreasing

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Customer reply replied 1 year ago
Now consider the inteval (1,infinity) let x=2
G (x)=2 (x-1)
This is the same as the last (3 answers) just with 2

G (x)=2 (x-1)
G (2)=2 (2 -1)
G (2)=2 (1 )
G (2)=2

greater than

increasing

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Customer reply replied 1 year ago
New problem. Step by step
Y=x^7-7x
Find the three intercepts
Customer reply replied 1 year ago
I know you'll need the points of inflection
Asymptotes
And relative extrema

Intercepts: -6th root of 7, 0, +6th root of 7

No asymptotes

Relative minimum: -6

Relative maximum: +6

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Customer reply replied 1 year ago
Inflection points

Inflection point is (0, 0)

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Customer reply replied 1 year ago
Y=7x^6-7
Differentiate y with respect to x
Part2
So y=0 when. X=?

y'(x) = 42x^5

Is the second part really asking when "y" is equal to 0, or is is "y-prime"?

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Customer reply replied 1 year ago
oh nevermind, you already did that one it just cleared my answer

Ok, great. I wasn't sure what they wanted for "c" there. It could have been just the x-coordinate, or it could have been the (x, y) ordered pair.

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Customer reply replied 1 year ago
Set 3
Screenshot (414).pngScreens...pngScreenshot (415).pngScreens...pngScreenshot (416).pngScreens...pngScreenshot (417).pngScreens...png
Customer reply replied 1 year ago
set 3 continued
Screenshot (418).pngScreens...pngScreenshot (419).pngScreens...pngScreenshot (420).pngScreens...pngScreenshot (421).pngScreens...png

I have the first 8 screenshots for Set 3. Please let me know if there are more, and when the deadline is for completion.

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Hi again,

Could you please post a screenshot of "Example 1"? It is referred to in problem #1, and I'm concerned that the "correct" answer might be slightly different than just calculating the straight integral.

Thanks,

Ryan

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Customer reply replied 1 year ago
I am so sorry. Got slammed with work and the deadline is tonight but I am gonna ask for an extension
Customer reply replied 1 year ago
4th set- If you cant finish by tonight it isnt a big deal. My professor lets us go back and complete them at the end of the semester and ive never asked for an extension before so Im sure he wont care with the holidays being so close
Screenshot (430).pngScreens...pngScreenshot (431).pngScreens...pngScreenshot (432).pngScreens...pngScreenshot (433).pngScreens...png

Here are the remaining solutions:

CalcSolutions

Please let me know if there are any issues.

Thanks,

Ryan

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Customer reply replied 1 year ago
Hey im sorry i havent responded been a busy week. And my teacher hasnt responded about extending so I havent been able to get you the last set..

Ok, thanks for the update.

Ryan
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Category: Calculus and Above
Satisfied Customers: 9,116
Experience: B.S. in Civil Engineering
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