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Find the margin of error...

Find the margin of error for the given values of c, s, and n.

C=0.90, s=3.9, n=49

E=_________

(Round to three decimal places as needed)

Construct the confidence interval for the population mean µ.

C= 0.95, x=8.1, s=0.3, and n=60

A 95% confidence interval for µ is _____, ______ (Round to two decimal places as needed.)

Construct the confidence interval for the population mean µ.

C= 0.95, x=16.5, s=6.0, and n=95

A 95% confidence interval for µ is _____, ______ (Round to two decimal places as needed.)

Use the confidence interval to find the estimated margin of error. Then find the sample mean.

A biologist reports a confidence interval of (2.5,3.3) when estimating the mean height in (in centimeters) of a sample of seedlings. The estimated margin of error is__________ , The sample mean is ________.

Find the minimum sample size n needed to estimate µ for the given values of c, s, and E.

C=0.98, s=6.6, and E=2

Assume that a preliminary sample has at least 30 members.

N=__________ (Round up to the nearest whole number)

You are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals or the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.

A random sample of 45 home theater systems has a mean price of $145.00 and a standard deviation of $18.30

Construct a 90% confidence interval for the population mean.

The 90% confidence interval is (____,____).

(Round to two decimal places as needed.)

Construct a 95% confidence interval for the population mean.

The 95% confidence interval is (____,____).

(Round to two decimal places as needed.)

You are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If the convenient, use technology to construct the confidence intervals.

A random sample of 49 gas grills has a mean price of $639.60 and a standard deviation of $57.40

The 90% confidence interval is ( _____,_____). (Round to two decimal places as needed.)

The 95% confidence interval is ( _____,_____). (Round to two decimal places as needed.)

You are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If the convenient, use technology to construct the confidence intervals.

A random sample of 45 eight-ounce servings of different juice drinks has a mean of 77.3 calories and a standard deviation of 42.7 calories.

The 90% confidence interval is ( _____,_____). (Round to one decimal places as needed.)

The 95% confidence interval is ( _____,_____). (Round to two decimal places as needed.)

People were polled on how many book they read the previous year. How many subjects are needed to estimate the number of books read the previous year within one book with 95% confidence? Initial survey results indicate that σ=11.5 books.

A 95% confidence level requires ______ subjects.

(Round up to the nearest whole number as needed.)

A doctor wants to estimate the HDL cholesterol of all 20-to 29- year old females. How many subjects are needed to estimate the HDL cholesterol within 4 points with 99% confidence assuming σ = 17.2? Suppose the doctor would be content with 95% confidence. How does the decrease in confidence affect the sample size required?

A 99% confidence level requires ____ subjects.

(Round up to the nearest whole number as needed.)

A 95% confidence level requires ____ subjects

(Round up to the nearest whole number as needed.)

Construct the indicated confidence interval for the population mean µ using (a) a t-distribution. (b) If you had incorrectly used a normal distribution, which interval would be wider?

C= 0.95, x=14.3, s=3.0, n=7

The 95% confidence interval using a t-distribution is (____,_____).

(Round to one decimal place as needed.)

In the following situation, assume the random variable is normally distributed and use a normal distribution or a t-distribution to construct a 90% confidence interval for the population mean. If convenient, use technology to construct the confidence interval.

In a random sample of 10 adults from a nearby county, the mean waste generated

Per person per day was 3.95 pounds and the standard deviation was 1.38 pounds.

Repeat part (a), assuming the same statistics came from a sample size of 600. Compare the results.

For the sample of 10 adults, the 90% confidence intervals is (____,____).

(Round to two decimal places as needed.)

For the sample of 600 adults, the 90% confidence intervals is (____,____).

(Round to two decimal places as needed.)

15. Use the given confidence interval to find the margin of error and the sample proportion. (0.728,0.754)

E=_____ (Type an integer or a decimal)

P=_____(Type an integer or a decimal)

C=0.90, s=3.9, n=49

E=_________

(Round to three decimal places as needed)

Construct the confidence interval for the population mean µ.

C= 0.95, x=8.1, s=0.3, and n=60

A 95% confidence interval for µ is _____, ______ (Round to two decimal places as needed.)

Construct the confidence interval for the population mean µ.

C= 0.95, x=16.5, s=6.0, and n=95

A 95% confidence interval for µ is _____, ______ (Round to two decimal places as needed.)

Use the confidence interval to find the estimated margin of error. Then find the sample mean.

A biologist reports a confidence interval of (2.5,3.3) when estimating the mean height in (in centimeters) of a sample of seedlings. The estimated margin of error is__________ , The sample mean is ________.

Find the minimum sample size n needed to estimate µ for the given values of c, s, and E.

C=0.98, s=6.6, and E=2

Assume that a preliminary sample has at least 30 members.

N=__________ (Round up to the nearest whole number)

You are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals or the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.

A random sample of 45 home theater systems has a mean price of $145.00 and a standard deviation of $18.30

Construct a 90% confidence interval for the population mean.

The 90% confidence interval is (____,____).

(Round to two decimal places as needed.)

Construct a 95% confidence interval for the population mean.

The 95% confidence interval is (____,____).

(Round to two decimal places as needed.)

You are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If the convenient, use technology to construct the confidence intervals.

A random sample of 49 gas grills has a mean price of $639.60 and a standard deviation of $57.40

The 90% confidence interval is ( _____,_____). (Round to two decimal places as needed.)

The 95% confidence interval is ( _____,_____). (Round to two decimal places as needed.)

You are given the sample mean and the sample standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Which interval is wider? If the convenient, use technology to construct the confidence intervals.

A random sample of 45 eight-ounce servings of different juice drinks has a mean of 77.3 calories and a standard deviation of 42.7 calories.

The 90% confidence interval is ( _____,_____). (Round to one decimal places as needed.)

The 95% confidence interval is ( _____,_____). (Round to two decimal places as needed.)

People were polled on how many book they read the previous year. How many subjects are needed to estimate the number of books read the previous year within one book with 95% confidence? Initial survey results indicate that σ=11.5 books.

A 95% confidence level requires ______ subjects.

(Round up to the nearest whole number as needed.)

A doctor wants to estimate the HDL cholesterol of all 20-to 29- year old females. How many subjects are needed to estimate the HDL cholesterol within 4 points with 99% confidence assuming σ = 17.2? Suppose the doctor would be content with 95% confidence. How does the decrease in confidence affect the sample size required?

A 99% confidence level requires ____ subjects.

(Round up to the nearest whole number as needed.)

A 95% confidence level requires ____ subjects

(Round up to the nearest whole number as needed.)

Construct the indicated confidence interval for the population mean µ using (a) a t-distribution. (b) If you had incorrectly used a normal distribution, which interval would be wider?

C= 0.95, x=14.3, s=3.0, n=7

The 95% confidence interval using a t-distribution is (____,_____).

(Round to one decimal place as needed.)

In the following situation, assume the random variable is normally distributed and use a normal distribution or a t-distribution to construct a 90% confidence interval for the population mean. If convenient, use technology to construct the confidence interval.

In a random sample of 10 adults from a nearby county, the mean waste generated

Per person per day was 3.95 pounds and the standard deviation was 1.38 pounds.

Repeat part (a), assuming the same statistics came from a sample size of 600. Compare the results.

For the sample of 10 adults, the 90% confidence intervals is (____,____).

(Round to two decimal places as needed.)

For the sample of 600 adults, the 90% confidence intervals is (____,____).

(Round to two decimal places as needed.)

15. Use the given confidence interval to find the margin of error and the sample proportion. (0.728,0.754)

E=_____ (Type an integer or a decimal)

P=_____(Type an integer or a decimal)

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