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walkereng
walkereng, Consultant
Category: Structural Engineering
Satisfied Customers: 2373
Experience:  Over 30 years of Structural Engineering experience.
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I have 2 rooms, 12 x 14 feet that share the 14' wall. I

Customer Question

i have 2 rooms, 12 x 14 feet that share the 14' wall. I would like to remove the 14' wall. these rooms are on the first floor. Above them are 2 x 8 floor joists, 16" on center that support the second floor living area. Above the second floor living area are trusses that distribute the room load to outside walls. These walls are parallel to the wall I wish to remove.
The beam needed to replace the load bearing wall should not be greater in height than the 2 x 8 joists it is supporting.
how many 2x8 's would be needed to construct the beam
Submitted: 1 year ago.
Category: Structural Engineering
Expert:  StructuralEng replied 1 year ago.

I can help

Expert:  StructuralEng replied 1 year ago.

You can't do that with 2x8s. You will need a steel beam

Expert:  StructuralEng replied 1 year ago.

What is the hoist length in rah side of the wall? Is there any ceramic tile?

Customer: replied 1 year ago.
What size I beam
Expert:  StructuralEng replied 1 year ago.

What is the joist length on each side of the beam?

Expert:  StructuralEng replied 1 year ago.

12'? Any ceramic tile?

Customer: replied 1 year ago.
I said the room (joists) are 12' on each side and there is no ceramic floor above
Expert:  StructuralEng replied 1 year ago.

W6x25 ASTM A992 Gr. 50. It's 6" deep x 6" wide and weighs 25 pounds per foot

Expert:  StructuralEng replied 1 year ago.

Hello. Do you have any other questions on this topic? If you could rate my answer, I would appreciate it.

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