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Sent to General Experts March 23 2005 at 11:45 AM
   

i have some data
A) Charle's Law
Data:      Volume - Temperature Pairs
          8.9cm       30c
          9.1cm       40c
          9.2cm       50c
          9.5cm       60c
          9.65cm      70c
          9.8cm       80c
I have to graph them and Least Sqaure calculations T (degrees centigrade) at absolute zero.
in order to do that, i have to prepare a graph in which i polot V against T in Celcius degree. This plot should show a linear relationship of the form V=aT +b. Use the least squares method to find the slope (a) and the y intercept (b) for this equation. Absolute zero on the Celcius scale will be the temperature at which V falls to zero: this temperature can be found by using the equation
   T of absolute zero in celcius degree = -b/a

Customer (name blocked for privacy)
Status:  Closed   Value: $7
Answer
March 23 2005 at 12:08 PM (23 minutes and 5 seconds later)
         
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I have your graph, but I can no longer insert it here as the maximum image size has been cut from 200K to 25k(!).  That is totally nuts, so I'll enquire with the JA management.  If you supply an email address I can send it to you that way.

Your equation is V = 0.0184T + 8.3448, and when it is applied to calculate absolute zero, the answer is -453 °.  This is clearly nonsense, since the figure should be about -273°.  It is however very close to the value for absolute zero in Fahrenheit (-459 °).  Have you got your temperature scales right?
Answer
March 23 2005 at 1:04 PM (55 minutes and 34 seconds later)
         
ACCEPTEDCheck Mark
OK - the image glitch has been fixed, so here it is.

Images available only to Customers.

Reply
March 23 2005 at 1:55 PM (51 minutes and 36 seconds later)
         
Reply to xarqi's Post: ok, thank you
could you answer me the another question that i posted? it is chemistry gas laws.

Thanks
Customer (name blocked for privacy)
Reply
March 23 2005 at 2:04 PM (8 minutes and 31 seconds later)
         
how did you get the answer -453?
Customer (name blocked for privacy)
Info Request
March 23 2005 at 2:06 PM (2 minutes and 30 seconds later)
         
-b/a

-8.3448/0.0184 = -453.5
Info Request
March 23 2005 at 2:09 PM (2 minutes and 42 seconds later)
         
Did you start with ice-water and then heat it while measuring
the volume increase in a fixed quantity of gas?

If you did, the 30 ° sounds a lot like the temperature you'd start
with in Fahrenheit.
Reply
March 23 2005 at 2:14 PM (5 minutes and 16 seconds later)
         
how did you get the 0.0184 and 8.3448?
Customer (name blocked for privacy)
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