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1. A machine produces 5-inch nails. A sample of 12 nails was selected and their lengths determined. The results are as follows: 4.91 4.97 4.80 4.81 4.93 4.82 4.84 4.81 4.97 4.95 4.82 4.86 Assuming that a = 0.05, test the hypothesis that the population mean is equal to 5. · State the null and alternate hypotheses · Calculate the mean and standard deviation · Determine which test statistic applies, and calculate it · Determine the critical value(s). · State your decision: Should the null hypothesis be rejected? 2. A sample of size n = 20 is selected from a normal population to construct a 95% confidence interval estimate for a population mean. The interval was computed to be (1.60 to 6.50). Determine the sample standard deviation.

Submitted: 14 days and 5 hours ago.
Category: Math
Value: $9
Status: CLOSED

Accepted Answer

1) Null hypothesis: Population mean µ = 5
Alternate hypothesis: Population mean µ ≠ 5
Mean = 4.87417
Standard deviation = 0.067076
t-test would be used.
t-statistic = (4.87417-5) / (0.067076/sqrt(12)) = -6.4984
critical values = -2.2010, 2.2010
As test-statistic lies in critical region, null hypothesis is rejected. The mean is different from 5.

2) Interval width = (6.5 - 1.6) = 4.9
2*t*s/sqrt(n) = 4.9
t-score for 95% confidence with d.f. 19 = 2.093
So, 2*2.093*s/sqrt(20) = 4.9
or s = 5.23494
So sample standard deviation is 5.23494.
or

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Expert: RRJha
Pos. Feedback: 100.0 %
Accepts: 
Answered: 11/8/2009

Graduate Student

Math Expert

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