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Meat plant estimates the mean net weight of ground chuck is 3 pounds. A sample of 36 package reveals the mean weight to be 3.01 pounds, with a standard deviation of .03 pounds.
a) what is the estimated population mean?
b) determine a 95% confidence interval for the population mean?

In addition:
Anoher survey of 50 execs who were laid off revealed it took a mean of 26 weeks to find another job. The standard deviation of the sample was 6.2 weeks. Costruct a 95% interval for the population mean. Is it reasonable that the population mean is 28 weeks? Justify your answer?

Submitted: 89 days and 3 hours ago.

Category: Math

Value: $9

Status: CLOSED

Level/Year: 1
Subject: 1

Already Tried:
1

Accepted Answer

Hi,

1.
a) 3.01
b) 3.01±1.960.03/sqrt(36) = (3.00, 3.02)

2.
26±1.966.2/sqrt(50) = (24.28, 27.72)

It is not reasonable that the population mean is 28 weeks. It is not in the confidence interval.

Accepts:
Expert:	abozer
Pos. Feedback:	99.9 %
Answered:	8/25/2009

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Level/Year: 1Subject: 1 Already Tried: 1

Accepted Answer

Hi,1.a) 3.01b) 3.01±1.96*0.03/sqrt(36) = (3.00, 3.02)2. 26±1.96*6.2/sqrt(50) = (24.28, 27.72)It is not reasonable that the population mean is 28 weeks. It is not in the confidence interval.

Related Math Questions

Level/Year: 1
Subject: 1

Already Tried:
1

Hi,

1.
a) 3.01
b) 3.01±1.960.03/sqrt(36) = (3.00, 3.02)

2.
26±1.966.2/sqrt(50) = (24.28, 27.72)

It is not reasonable that the population mean is 28 weeks. It is not in the confidence interval.