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1. Multiply
(6x-y)(11y-5z)


2. (x^2+11x+18) divided by (x+2)


3. Factor completely. If the polynomial is prime, state this
4a^3+12a^2-72a


4. Factor completely. If the polynomial is prime, state this.
y^2-2/7y+1/49


5. Factor completely. If the polynomial is prime, state this
5n+5w–n^2–nw


6. Solve by factoring and using the principle of zero products
12n^2+36n=0

7. The product of two consecutive integers is 8 less than 8 times their sum. Find the integers

Submitted: 94 days and 23 hours ago.
Category: Math
Value: $15
Status: AWAITING CUSTOMER ACTION
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Optional Information

Level/Year: 2
Subject: Algebra 2

Already Tried:
Just checking some of my answers. Thanks.

Accepted Answer

Sure thing!

 

1. Multiply
(6x-y)(11y-5z)

use foil:

66xy - 30xz - 11y^2 + 5yz


2. (x^2+11x+18) divided by (x+2)
factor the first part:

(x+2)(x+9)

divide out the x+2:

x+9

3. Factor completely. If the polynomial is prime, state this
4a^3+12a^2-72a
pull out 4a:

4a(a^2+3a-18)

factor the inside:

4a(a+6)(a-3)



4. Factor completely. If the polynomial is prime, state this.
y^2-2/7y+1/49
This is a perfect square:

(y-1/7)^2

5. Factor completely. If the polynomial is prime, state this
5n+5w-n^2-nw
use the groups method:

5(n+w) - n(n+w)

rearrange:

(5-n)(n+w)



6. Solve by factoring and using the principle of zero products
12n^2+36n=0
factor:

12n(n+3) = 0

12n = 0, so n = 0

n+3 = 0, so n= -3

solutions: 0, -3


7. The product of two consecutive integers is 8 less than 8 times their sum. Find the integers

x(x+1) = 8(x+x+1) - 8

expand:

x^2 + x = 16x

x^2 - 15x = 0

x(x-15) = 0

x = 0 or 15

so they are 0 and 1 OR 15 and 16

 

Let me know if you have any questions,

Scott

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Expert: Scott
Pos. Feedback: 100.0 %
Accepts: 
Answered: 8/19/2009

MIT Graduate

College degree in math... proficient in all levels -- from algebra to calculus

94 days and 23 hours ago.

Reply

thanks

Posted by Scott 94 days and 23 hours ago.

Info Request

You're welcome!

-Scott

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