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Explain how the following scenario is possible, using a coin toss and fictitious data: As the number of trials increases, the differences between the number of actual and expected successes tends to grow, but the difference between the percentage of actual and expected successes tends to decrease.
Trials
Tosses
Number of Heads (Actual)
Number of Heads (Expected)
Difference between Numerical Totals
Percentage of Heads (Actual)
Percentage of Heads
(Expected)
Difference between Percentages
1
100
52
50
2
.52
.50
0.02
2
100
54
52
2
.54
.52
0.02
3
100
48
54
6
.48
.54
0.06
4
100
51
48
3
.51
.48
0.03
Please review the Task Directions and provide this explanation and fictitious data. Good work using the recommended table but the scenario is not demonstrated correctly. The number of trials needs to increase while the numerical difference increases and the percentage difference decreases. Perhaps using trial #1 as 100 tosses and trial #2 as 1000 trials would be simplest. Then choose the numbers to illustrate the given scenario. The expected percentage of heads should always be 50%
Submitted: 283 days and 14 hours ago.
Category: Math
Value: $9
Status: CLOSED
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Optional Information
Level: Junior; Subject: Math
Already Tried:
I created a table with four different tosses, but it was incorrect.
Accepted Answer
Hi, here is the answer
We used 3 trials
#1) 100 tosses:
Tosses
100
Number of Heads (Actual)
52
Number of Heads (Expected)
50
Difference between Numerical Totals
2
Percentage of Heads (Actual)
0.52
Percentage of Heads (Expected)
0.5
Difference between Percentages 100
0.02
#2) 500 tosses:
Tosses
500
Number of Heads (Actual)
255
Number of Heads (Expected)
250
Difference between Numerical Totals
5
Percentage of Heads (Actual)
0.51
Percentage of Heads (Expected)
0.5
Difference between Percentages 100
0.01
#3) 1000 tosses:
Tosses
1000
Number of Heads (Actual)
508
Number of Heads (Expected)
500
Difference between Numerical Totals
8
Percentage of Heads (Actual)
0.508
Percentage of Heads (Expected)
0.5
Difference between Percentages 100
0.008
the differences between the number of actual and expected successes tends to grow
values are: 2,5 and 8
the difference between the percentage of actual and expected successes tends to decrease.
values are:0.02,0.01 and 0.008
Any bonus is appreciated
Thanks
Steve
Edited by Steve on 2/12/2009 at 1:17 PM
Expert:
Steve
Pos. Feedback:
100.0 %
Accepts:
Answered:
2/12/2009
Teacher
I teach Calculus and Probability in an University since 1994
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