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How to divide an area, 6 units by 6 units into 4 areas of equal size AND shape. Each of the four areas must include one circle and one triangle, the location of which is described in the question details.
The area is 6 units by 6 units (total of 36 units). This would be easy if I could post a picture but will describe it and you can make your own picture. First draw a sqare and divide it up into 36 small sqares (6 by 6). Then, number each square, starting with the lower left hand corner from 1 to 36. Number the squares from left to right, bottom to top (The first row should be 1 to 6, and the second row should start with 7 above the 1, and so on). Then put a circle in number 1, 18, 22, & 24. Put a triangle in number 7, 10, 11 & 25. (Now that you know the locations of the circles and triangles, the numbers are no longer necessary.)
Submitted: 290 days and 19 hours ago.
Category: Math
Value: $15
Status: CLOSED
Accepted Answer
Hi, I was about to give up on this one but when writing to you to argue it was impossible I argued out the solution :-D
Solution
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Derrivation of the answer
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The red lines shows where we definitely need our shape's edge to 'go along'.
Consider triangle in box 25 (top left one)
That can only be in the shape with either circle in box XX XX XXXXXX in both 24. The other two circles would cause shapes to be isolated.
The circle in box 24 can only be in one shape that contains itself and the triangle in box 25 namely
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Clearly we can only put one more of these shapes in the rest of the grid.
Hence triangle 25 must be with circle 22
Now arises the problem of what triange to pair circle 24 with.
Clearly triangle 7 is no good.
Triangle 10 would require a kind of zig zag shape that would not accommodate triangle XX XXX XXXXXX 18 which must subsequently be paired.
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Hence circle 18 must be paired with triangle 11
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Circle 18 then shows we need a 'sticky out' of two blocks (3 blocks in total). Initially this seemed impossible but then it click and here is the solution
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Got there ;-)
Edited by Ben Brown on 2/5/2009 at 2:10 PM
Expert:
Ben Brown
Pos. Feedback:
100.0 %
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Answered:
2/5/2009
Mathematician
First Class Honours in Mathematics from Oxford University
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