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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and Train B is traveling at 90 miles per hour. Train A passes a station at 7:20 A.M. If train B passes the same station at 7:32 A.M, at what time will train B catch up to train A?

Submitted: 307 days and 8 hours ago.

Category: Math

Value: $9

Status: AWAITING CUSTOMER ACTION

Level: Collage; Subject: Algebra

Already Tried:
Everything!

Posted by abozer 307 days and 8 hours ago.

Answer

Hi, Welcome to Justanswer,

Train B passes the station 12 minutes after A.

In 12 minutes train A goes 80(12/60) = 16 miles.

Train B is 10 miles faster than train A.

It catches up train A after 16/10 = 1.6 hours. Or 1.6(60) = 96 minutes.

The time will be 9:08 A.M. at that time.

307 days and 8 hours ago.

Reply

Thanks. I put that in my exam as my answer:)

Answer

You're Welcome.

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Expert:	abozer
Pos. Feedback:	99.9 %
Answered:	1/19/2009

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Question

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and Train B is traveling at 90 miles per hour. Train A passes a station at 7:20 A.M. If train B passes the same station at 7:32 A.M, at what time will train B catch up to train A?

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Level: Collage; Subject: Algebra Already Tried: Everything!

Answer

Hi, Welcome to Justanswer,Train B passes the station 12 minutes after A. In 12 minutes train A goes 80(12/60) = 16 miles.Train B is 10 miles faster than train A.It catches up train A after 16/10 = 1.6 hours. Or 1.6(60) = 96 minutes.The time will be 9:08 A.M. at that time.

Reply

Thanks. I put that in my exam as my answer:)

Answer

You're Welcome.

Related Math Questions

Level: Collage; Subject: Algebra

Already Tried:
Everything!

Hi, Welcome to Justanswer,

Train B passes the station 12 minutes after A.

In 12 minutes train A goes 80(12/60) = 16 miles.

Train B is 10 miles faster than train A.

It catches up train A after 16/10 = 1.6 hours. Or 1.6(60) = 96 minutes.

The time will be 9:08 A.M. at that time.