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I need a step by step solution to this problem not just the answer. PlEASE DON'T DO THE ANSWER IN EXCEL!Consider the formula P=67.38*(1.026)t. If we let P represent the population of Mexico in year "t" where t is the number of years from 1980 ,confirm that this formula gives the same population values as those given in this example. YEAR:1980 POPULATION IN MILLIONS:67.38;YEAR:1981 POPULATION IN MILLIONS:69.13;YEAR:1982 POPULATION IN MILLIONS:70.93;YEAR:1983 POPULATION IN MILLIONS:72.77;YEAR:1984 POPULATION IN MILLIONS:74.66;yEAR:1985 POPULATION IN MILLIONS:76.60;YEAR:1986 POPULATION IN MILLIONS:78.59; A)What would the population in 1990 have been if growth had continued in this same pattern?B)How many years beyond 1980 will it take to double the population assuming the growth continues in the same pattern?

Submitted: 316 days and 11 hours ago.
Category: Math
Value: $9
Status: AWAITING CUSTOMER ACTION
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Level: Year 4

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Accepted Answer

Hi, again

Formula is : P=67.38*(1.026)^t

YEAR:1980 POPULATION IN MILLIONS:67.38; t=0 then P=67.38*(1.026)^0=67.38
YEAR:1981 POPULATION IN MILLIONS:69.13 t=1 then P=67.38*(1.026)^1=69.13
YEAR:1982 POPULATION IN MILLIONS:70.93 t=2 then P=67.38*(1.026)^2=70.93
YEAR:1983 POPULATION IN MILLIONS:72.77 t=3 then P=67.38*(1.026)^3=72.77
YEAR:1984 POPULATION IN MILLIONS:74.66 t=4 then P=67.38*(1.026)^4=74.67
yEAR:1985 POPULATION IN MILLIONS:76.60 t=5 then P=67.38*(1.026)^5=76.6
YEAR:1986 POPULATION IN MILLIONS:78.59 t=6 then P=67.38*(1.026)^6=78.6

Year 1990, t =10 then P=67.38*(1.026)^10=87.097 millions

we have to find t where 2(67.38)=67.38(1.026)^t

then 1.026^t=2

tLn(1.026)=Ln(2)

t= Ln(2)/Ln(1.026)=27 (aprox)

so year is 2007

Thanks

Steve

Any bonus is appreciated

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Expert: Steve
Pos. Feedback: 100.0 %
Accepts: 
Answered: 1/10/2009

Teacher

I teach Calculus and Probability in an University since 1994

316 days and 10 hours ago.

Reply

I have a question what is the answer to my "B" portion of the question
How many years beyond 1980 would it take to double the population assuming the growth continues in the same pattern?

Posted by Steve 316 days and 10 hours ago.

Info Request

A) 87.097 millions
B) 27 years beyond 1980 (Year 2007)

Thanks

Steve

316 days and 10 hours ago.

Reply

Thank You.

Posted by Steve 316 days and 10 hours ago.

Info Request

Thanks for all ,you can request me in the future (as Steve)

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