JustAnswer > Math
Ask A Question|Register|Login|Help
JustAnswer

Math

Ask a Math Question, Get an Answer ASAP!

Have your own Math question?

9 Math Tutors are Online Now
characters left:
Not a Math Question?

Related Math Topics:

  • Solve
Bookmark and Share

Question

Find the vertex and graph of y= -x^2 +6x - 5.5

Submitted: 527 days and 21 hours ago.
Category: Math
Value: $9
Status: CLOSED

Accepted Answer

y= -x^2 +6x - 5.5

we differentiate

y' = -2x + 6

Set y' = 0 and solve for x to find vertex:

0 = -2x + 6

2x = 6

x = 3.

now lets plug in x = 3 into the function to find the y-coordinate of the vertex:

y = -3^2 + 6*3 - 5.5 = 3.5

So vertex = (3, 3.5)


Since the coefficient of x^2 is negative, the vertex is a maximum and the graph will look like this:

graphic
View Full Image


Sincerely,
SK1llz


Sk1llz39723.3482927083

Picture
Expert: Sk1llz
Pos. Feedback: 100.0 %
Accepts: 1525
Answered: 10/2/2008

Mastermind

Mathematics, Statistics and Physics

Related Math Questions

  • How do you transfer volume into gallons
  • 1. Solve the following system graphically x=y-4 and 2x=4y
  • For Scott, Hi Scott, was wondering if you could help me
  • Surveys have been widely used by politicians around the worl...
  • In random samples of 25 from each of two normal populations,
  • a) Calculate the probability of a type ii error for the foll...
  • Calculate the following: a) Determine the sample size ne...
  • a) From the information given here, determine the 95% confid...



Disclaimer: Information in questions, answers, and other posts on this site ("Posts") comes from individual users, not JustAnswer; JustAnswer is not responsible for Posts. Posts are for general information, are not intended to substitute for informed professional advice (medical, legal, veterinary, financial, etc.), or to establish a professional-client relationship. The site and services are provided "as is" with no warranty or representations by JustAnswer regarding the qualifications of Experts. To see what credentials have been verified by a third-party service, please click on the "Verified" symbol in some Experts' profiles. JustAnswer is not intended or designed for EMERGENCY questions which should be directed immediately by telephone or in-person to qualified professionals.
Question List | Become an Expert | Terms of Service | Security & Privacy | About Us
© 2003-2010 JustAnswer Corp.