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three men and a monkey trapped on an island gathered coconuts on their first day and piled them all together that evening so they could be divided evenly the next day. one man got up during the night and took half of the pile plus 1/2 a coconut, also each of the other two men did likewise taking half of the pile plus 1/2 a coconut. in the morning there was one coconut left. the men got into an argument over the coconuts and while they argued the monkey ran off with the remaining one so they had none left. how many coconuts did they gather on the first day?

Submitted: 420 days and 22 hours ago.
Category: Math
Value: $15
Status: CLOSED
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Level: eigth grade; Subject: math

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Accepted Answer

Hi there!

 

The starting amount is "x".

 

The first man takes x/2 + 1/2, leaving:

x - (x/2 + 1/2)

= x/2 - 1/2

 

The next man takes half of that (plus a 1/2 coconut):
(x/2-1/2)/2 + 1/2

= x/4-1/4 + 1/2

= x/4+1/4

Leaving:

(x/2-1/2) - (x/4+1/4)

= x/4-3/4

 

The final man takes half of that (plus 1/2 coconut):

(x/4-3/4)/2 + 1/2

= x/8-3/8 + 1/2

= x/8+1/8

Leaving:

(x/4-3/4) - (x/8+1/8)

= x/8-7/8

 

There was 1 coconut remaining (which the monkey took), so set that to 1:

x/8 - 7/8 = 1

Add 7/8:

x/8 = 15/8

Multiply by 8:

x = 15

 

There were 15 coconuts on the first day.

 

Let me know if you have any questions at all. If not, thanks for pressing "Accept".

 

-Scott

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Expert: Scott
Pos. Feedback: 100.0 %
Accepts: 
Answered: 9/27/2008

MIT Graduate

College degree in math... proficient in all levels -- from algebra to calculus

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