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A stack of $1 notes and a stack of $5 notes have a mass of 108 grams. The stack of $1 notes has a mass of 26 grams more than the stack of $5 notes. What is the mass of each stack? Tell how you solved the problem. (i.e. the mass of one note is 1 gram)

Submitted: 438 days and 5 hours ago.
Category: Math
Value: $15
Status: AWAITING CUSTOMER ACTION
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Optional Information

Level: Fifth Grade; Subject: Math

Already Tried:
We tried 108-26=82. Then, we tried 82-26=56. Next, we tried 108-56=52 We know 52-56=108, but neither number is 26 more than the other.

Posted by Scott 438 days and 5 hours ago.

Answer

Hi there!

 

Call the ones "O" and the fives "F".

 

Let's set up two equations:

Based on the total mass of the notes:

O + F = 108

 

Based on the difference between masses:

O - F = 26

 

Now, let's add the two equations together:

O + F + O - F = 108 + 26

 

Simplify:

2O = 134

 

Divide by 2:

O = 67

 

To get F, use the second equation we made:

O - F = 26

67 - F = 26

F = 67-26

F = 41

 

$1 notes: 67 grams

$5 notes: 41 grams

 

Let me know if you have any questions. If not, thanks for pressing "Accept".

 

-Scott

438 days and 5 hours ago.

Reply

Is there a simplier way to get the answer. My daughter is just a fifth grader. She hasn't done a lot with algebra. If not, can you explain the O+F+O-F=108=26. She isn't sure how you got the 20.

Accepted Answer

Oh, I hadn't realized what grade this was for (when I first opened this, the "Fifth Grade" wasn't showing). Smile

 

If you want to solve this without algebra (which I'm guessing you want), you can do it like this...

First divide the 108 by 2, so that we have half the notes as each type:

108/2 = 54

 

Now, remember that the difference between them has to be 26. Half of that difference has to be above and half as to be below. Let's divide the 26 by 2:

26/2 = 13

 

Add and subtract that with 54:

54+13 = 67

54-13 = 41

 

That's the non-algebra way to get 67 and 41. All you are doing is splitting both the total weight in half, and then splitting the weight difference in half.

 

Please do let me know if you have any other questions, or if your daughter is still confused. You don't have to accept until you understand this completely.

Scott

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Expert: Scott
Pos. Feedback: 100.0 %
Accepts: 
Answered: 9/9/2008

MIT Graduate

College degree in math... proficient in all levels -- from algebra to calculus

438 days and 5 hours ago.

Reply

Thank you so much. She was able to explain what you should us to me.

Posted by Scott 438 days and 5 hours ago.

Info Request

Glad to help :)

 

-Scott

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