the length of a rectangular piece of steel in a bridge is 5 meter less than triple the width. the perimeter of the piece of steel is 54 meters. find the length of the piece of steel. find the width of the piece of steel.
Hi, Thank you for using JustAnswer. Here is the solution: Let L represent the length of the piece of steel, and let W represent the width. Since the length is 5 meters less than triple the width, we can write the following equation: L = 3W - 5 The perimeter of the rectangle is equal to: P = 2L + 2W Since the perimeter is equal to 54 meters, we can write the following equation:2L + 2W = 54Using the first equation to substitute for L in the above equation gives:2(3W - 5) + 2W = 546W - 10 + 2W = 548W - 10 + 10 = 54 + 108W = 64W = 64/8W = 8 metersThe length is then equal to 3W - 5 = 3(8) - 5 = 19 meters.(As a check, the perimeter is 2(19) + 2(8) = 38 + 16 = 54.)Solution: Length = 19 metersWidth = 8 metersPlease feel free to ask if you have any questions about this solution.Thanks,Ryan
B.S. in Civil Engineering