Use the law of sines to solve the triangle, C=57°40', c=34.1, b=26.1
Thanks for visiting JustAnswer and your question.Let a, b and c be the sides of the triangle and A, B and C be the corresponding opposite angles. The law of sines states that:a/sinA = b/sinB = c/sinCWe are given angle C and sides c and b as:C = 57.6667 degreesb = 26.1c = 34.1Now, we can useb/sinB = c/sinC to find angle B.sinB = b sinC/csinB = 0.6467B = 40.3 degrees = 40 degrees 17.7 minutesNow, sum of angles in a triangle is 180. i.e.A + B + C = 180A = 180 - (B + C) = 180 - (40.3 + 57.6667) = 82.03 degreesNow, using law of sines againa/sinA = c/sinCa = c sinA/sinC = (34.1) sin(82.03)/sin(57.6667) = 39.96Hence the three sides are:a = 39.96b = 26.1c = 34.1and the three angles are:A = 82.03 degreesB = 40.3 degreesC = 57.6667 degreesI hope this helps.
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