JAMES, ASHLEY, AND NICOLE, ALL SIBLINGS VISITING SCENE75, HAVE COLLECTIVELY WON A TOTAL OF 340 REDEMPTION PRIZE POINTS. THEIR MOTHER, KATHY, DECIDES HOW THE POINTS WILL BE SPLIT AMONGST THE THREE CHILDREN. SHE SAYS THAT JAMES AND ASHLEY BOTH BEHAVED VERY POORLY TODAY, THOUGH JAMES BEHAVED EVEN WORSE THAN ASHLEY. KATHY ASKS YOU TO SPLIT THE POINTS SUCH THAT JAMES RECEIVES 40 POINTS FEWER THAN ASHLEY AND THAT ASHLEY RECEIVES 80 POUNTS FEWER THAN NICOLE. HOW MANY POINTS DOES EACH CHILD RECEIVE?
Optional Information: Level/Year: Subject: Algebra Already Tried: reason the problem j== 40-a A= 80-N n =340 (40-a)+(80-N)=340
Thank you for your question.
Define J, A, and N, as the points James receives, Ashley receives, and Nicole receives, respectfully.
J + A + N = 340
J + (J + 40) + (J + 40 + 80) = 340
3J + 160 = 340
3J = 180
J = 60
James: 60 points
Ashley: 100 points
Nicole: 180 points
Osbert