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Here are the solutions:
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Ok, no problem.
From the table, the p-value for the test is listed in the last column, under the heading "Sig F". The value is 0.0000009.
This p-value is less than any of the values of alpha listed ("0.10, 0.05, 0.01, and 0.001"). As a result, the linear regression model is significant at all of those values of alpha.
Please note that there are issues with the ANOVA table that was given in this problem. I already mentioned the number of degrees of freedom for the Residual line being incorrect, although I suspect that is simply a typo. There is also some significant rounding off of the MS values, and by extension the F value. When I use either the given F value, or the "correct" value, I get a p-value of 0.0000001, which is significantly less than the given value of 0.0000009.
I mention all this only because I can foresee some potential issues with the "correct" answers, as it is impossible for me to know whether your course expects you to blindly use the values as given, or if they expect you to calculate things yourself. If any of this comes back to you marked incorrect, please feel free to contact me. I'll be happy to try to help straighten things out if I can.