Thank you for using the site. I'll be happy to help you with this.
Assuming that the scores are normally distributed, the cut-off score marking the top 15% is:
z for top 15% = 1.036
Cut-off score = µ + zs = 87 + (1.036)(8) = 102.54
Since the score of 110 is greater than the cut-off score of 102.54, yes, that individual would be acceptable.
Please feel free to ask if you have any questions about this solution.