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Ashok Kumar, Electrical Engineer
Category: Math Homework
Satisfied Customers: 3107
Experience:  Master's Degree
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# Logs and sets

### Customer Question

logs and sets
Submitted: 1 year ago.
Category: Math Homework
Expert:  Ashok Kumar replied 1 year ago.

Kindly forward the questions.

Customer: replied 1 year ago.
Hi Ash Kumar i need answers for question 4 and 5regards
Expert:  Ashok Kumar replied 1 year ago.

thanks. when this is due? Kindly inform.

Customer: replied 1 year ago.
in 30 minutes
Expert:  Ashok Kumar replied 1 year ago.

4.(a)(i) 2

(ii)

(b)(i) 0.4029

(ii) 1.4307

5.(a)(i) true

(ii) true

(iii)true

(iv)true

(v) true

(b)(i) range: (1 infinity)

(ii)domain of f^-1 is not same as domain of f; hence, we say that it has no inverse.

f^-1 = sqrt[(x-1)/2]

Expert:  Ashok Kumar replied 1 year ago.

I am not sure about 4(a) (ii).

Customer: replied 1 year ago.
can i get pleasew get working for 4 b part 1 and 2 as they both are 3 marks each
Customer: replied 1 year ago.
just leave questions 4 and 5i need worked solutions for quest 3 part b 1,2 and 3
Expert:  Ashok Kumar replied 1 year ago.

4(b) (i) taking ln, we get -1.73 lnx= ln4.82

lnx = ln4.82/-1.73 = -0.90912

x = e^-090912 =0.4029

(ii)taking ln, we get -xln2 = ln0.1

x = -ln0.1/ln2 = -1.4307

Expert:  Ashok Kumar replied 1 year ago.

3.(b) (i) it can not represent as y =x^4+5 represents so that y is always above x-axis. the graph shown is below x-axis also. Hence, it can not represent given graph.

(ii) it represents the given graph.

(iii) it represents linear function but given graph is not linear; hence, it does not represent the given graph.

Expert:  Ashok Kumar replied 1 year ago.

Customer: replied 1 year ago.
I need numeric solutions for questions 3 b part 1-3
Expert:  Ashok Kumar replied 1 year ago.

it is not clear how numeric solution is possible.

Customer: replied 1 year ago.
Question 5 b part 1 and 2is not correct.
Expert:  Ashok Kumar replied 1 year ago.

I was not sure what R and Q are representing.

Expert:  Ashok Kumar replied 1 year ago.

i will reply after 6-7 hours if there is any query.

Customer: replied 1 year ago.
It's sets i need solutions now
Customer: replied 1 year ago.
For questions 5 b part 1 and 2
Expert:  Ashok Kumar replied 1 year ago.

5.(b)(i) range: (1 infinity)

(ii)domain of f^-1 is not same as domain of f; hence, we say that it has no inverse.

f^-1 = sqrt[(x-1)/2]

Expert:  Ashok Kumar replied 1 year ago.

5.(b)(i) Range is that y will vary from 1 to infinity. we can wriite range: 1≤y≤∞.

(ii) y = 2x^2+1

For getting inverse, we interchange, x and y and get

x= 2y^2+1

or y = sqrt[(x-1)/2]

Hence, f^-1 = sqrt[(x-1)/2]

Expert:  Ashok Kumar replied 1 year ago.