these are statistics questions:http://www.mediafire.com/?akda 7luv8d7x4y8http://www.mediafire.com/?dks1is2va05094zhttp://www.mediafire.com/?ultkhkd9gqaqdqbhttp://www.mediafire.com/?ivkoi171wqvbxeuhttp://www.mediafire.com/?nc2nc33blvfpeeyhttp://www.mediafire.com/?lax1zwjahn057z5
Hi,
I will check the links now
Steve
I can´t access to the files, can you upload them using www.wikisend.com ?
I have checked the files and I think only the first one is not working, the rest can be viewed properly
Would you like me to help you on these? please reply.
Hi yes please sorry for the late reply. Please help me.
What date and what time do you need the answers? also I can't open this file http://www.mediafire.com/?akda 7luv8d7x4y8 ( it is the first one)also, where is the data for the last file (anova)http://www.mediafire.com/?lax1zwjahn057z5Lastly, can we increase the quote to $20 since the 5 questions are tough (hypothesis testings) and some have so many sub questions like the 3rd and 4th fileplease reply asap
Hi yes please sorry for the late reply. Please help me.Try this:(the last link is he first one that didn't work)http://wikisend.com/download/598922/1.docxhttp://wikis end.com/download/361060/2.docxhttp://wikisend.com/download/825648/3.docxhttp://wikisend.com/download/782488/4.docxhttp://wikisend.com/download/734476/5.docxhttp://wikisend.com/download/765810/6.docxI will upload data for 5 soon, thanks so much for helping :)
What date and what time do you need the answers?
If you could please finish it by 24hrs that would be great
ok I send the answers the soonest possible time, thanks
here is part 5:http://wikisend.com/download/218816/12.35.docxandhttp://wikisend.com/download/733492/12.39.docx
ok
How are you going with these??
Yup, I am almost through it,today I will send the answers
thanks :)
welcome sir
here are the complete answers except page 5:for page 1 http://www.mediafire.com/?akda%207luv8d7x4y8for page 2:http://www.mediafire.com/view/?gzpupb32lvelbmqfor page 3:http://www.mediafire.com/?3adqncdsib8bmn4for page 4:http://www.mediafire.com/view/?qtxih6n2blxfy8cfor page 6:http://www.mediafire.com/view/?boa824cc7d8wjczfor page 5, do I need to answer both 12.35 and 12.39 file or the last one only (12.39) please reply asapPlease Leave a POSITIVE FEEDBACK to Credit me. BONUS is welcome.Thanks.If you need my help asap, just write in the first part of your question: "For Mr Glenn G. only!" Thanks again
Experience: Mathematics (Pre Calculus and Calculus, Statistics, etc.)
If you could do both that'll be great.
If you could do both that'll be great.The first link page 1 doesnt work??
Yup I will do them today, please choose accept so that I can be credited for the effort of helping you,Please Leave a POSITIVE FEEDBACK to Credit me. BONUS is welcome.Thanks.If you need my help asap, just write in the first part of your question: "For Mr Glenn G. only!" Thanks againalso kindly add some more bonus since the questions are too long and tedious
Hi, I need a bit more help for page 3 part d,Fo the 95% CI whaat formula did you used to find S and can you do step by step for the other parts I don't understand it...t(alpha/2) and Mx what's these?? Yo +- t(alpha/2)*SE*sqrt(1/n +(Xo-Mx)^2/(n-1)*S^2x
s here is the standard deviation of the x variable, its formula is s = sqrt [summation of (x - mean)^2 / (n-1)]in what specific page are you referring to that you want a more detailed explanation?
Page 3 please part d
Mx is the mean of X so just add all the ten values of X then divide the sum by 10 then you will get Mean of x (Mx) = 0.495111.93 is obtained by substituting x = 0.50 in the regression equation;Yhat = 6.51+ 10.83xYhat = 6.51+ 10.83*0.50Yhat = 11.925 or approx. 11.93t(α/2) is the two tailed critical t value, you need to look at the t distribution table, and since n = 10, the degrees of freedom = n -2 = 10 - 2 = 8, so at alpha = 0.05 (two tailed) and df = 8, the critical t value at the t table is t = 2.306Sx is the standard deviation of the x variable,to compute for it, subtract each score in the x variable by the mean of x, then after that, square each differences, then get the sum of the squared differences, then divide the sum by n - 1 = 10 - 1 = 9, then finally get the square root of the quotient, you will get a value of Sx = 0.0648also you can use scientific calculator (SD mode) in computing standard deviation or even excel (just use the function =stdev( then select all the scores in the x variable) then press enter
Thanks for clarifying it out, I understand now.And how a you going with page 5, could you also resend page 1 it didn't work Thanks
ok sir I will send page 5 the soonest possible time, here is the link for page 1: http://www.mediafire.com/view/?ac85h21cb9ercl5 Dear Customer, do not forget to accept, so that I will be compensated for the time and effort of helping you, also any additional bonus will be appreciated Please Leave a POSITIVE FEEDBACK to Credit me. BONUS is welcome.Thanks. If you need my help asap, just write in the first part of your question: "For Mr Glenn G. only!" Thanks again Thanks sir for your bonus (if you are planning to give me) :)Mr. Glenn G.41085.6156960648