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David
David, Post-Doctoral Degree
Category: Math Homework
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Experience:  Theoretical Physics
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The length L of a rectangle is 1 foot more than its width W

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The length L of a rectangle is 1 foot more than its width W and its area is 56f^2. Find length and width of the rectangle.

David :

hello

David :

welcome to JA

David :

here is how you do it

David :

say the width is x

David :

and hence the length becomes x+1

David :

the area is x(x+1) = 56

David :

or

David :

x^2+x-56=0

David :

(x+8)(x-7)=0

David :

x=7 and x=-8

David :

the negative number is XXXXX physical

David :

so we have width=7

David :

and hence the length =7+1=8

David :

Answer: length= 8 feet, width =7 feet

David :

DONE

David :

hope this helps

Customer:

Thank you - but what does 56f^2 mean? is not the area then 3136? I am confused.

David :

it means 56 square feet

David :

like this ft²

David :

note it is not 56*56

Customer:

Oh, no wonder ! I thought it meant 56*56. Boy, I had that incorrect. Thank you.

Customer:

Very simple problem now.

David :

yep :-)

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