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Ho: μ = 1800Ha: μ ≠ 1800
This is a two-tailed test.
significance level = 0.05
critical values: z = -1.96 and 1.96
test statistic = (1975 - 1800)/(550/sqrt(35))
The test statistic is not more extreme than the critical values.
So we cannot reject the null hypothesis.
We don't have sufficient evidence to conclude that the average back charge is different than $1800.
Please let me know if you have any questions.
I'm still trying to work it out.....
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I got It!!!!!! Thanks for all you help