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Hi,

hi

The question is asking for f(7)

correct

7 fits into the second interval, x ≥ 7,

Substitute 7 in the second part of the function as follows,

= -2(7)^2 + 7

= -91

Let me know if you have any questions

so i dont have to find the answers to both?

no.

the answer for the wholeproblem is -91

yes.

ok then its the same problem but now i have to find f(2)

2 fits into the first interval, 0 < x < 7,

Substitute 2 in the first part of the function,

= 10(2) + 6

= 26

That's it.

26

Let me know if you have any other questions.

are u able to help again or do I need to repost?

I can help.

f(x)= 9x^3+8x-10 find f(5)

f(5) = 9(5)^3 + 8(5) - 10

= 9(125) + 40 - 10

= 1125 + 40 - 10

= 1155

f(x)= 9x^3+8x-10

find f(-3)

f(-3) = 9(-3)^3 + 8(-3) - 10

= 9(-27) - 24 - 10

= -243 - 24 - 10

= -277

I appreciate if you accept before asking more questions.

yep this last one then i will accept and then i'll repost and maybe you can help me with more.

f(x)= 9x^3+8x-10 find f(x+c)

Sure.

f(x + c) = 9(x + c)^3 + 8(x + c) - 10

= 9(x^3 + 3x^2c + 3xc^2 + c^3) + 8(x + c) - 10

= 9x^3 + 27x^2c + 27xc^2 + 8x + 8c - 10

= 9x^3 + (27c)x^2 + (27c^2 + 8)x + 8c - 10

Let me know if you have any questions.

the last line is the final answer

i have to solve for the final answer

Yes.

It is in terms of x and c

You can also use the one before the last one.

I rearranged in the last step.

yeah for some reason that wasnt correct

f(x)= 2x+9 divided by xsquared -5x-6 find the domain

The denominator cannot be zero.

x^2 - 5x - 6 ≠ 0

(x - 6)(x + 1) ≠ 0

x ≠ 6

x ≠ -1

So the domain is,

{x| all real numbers x ≠ 6 and x ≠ -1}

That's the answer.

so would i just say real numbers and 6 and -1

or just all real numbers

all real numbers except 6 and -1.

f(x)=2x+6 find f(x+h)

You said you were going to accept and repost.