I understand that it is not that simple. For starters the house is in southern CT. The house is a cluster-mess. It started as a 2,000 square ft. with a Peerless WV3 - max 1.1gph. He has doubled the size of the house, and now has added the hot water load.
From what I gather, the outside perimeter of the house has doubled, and the building materials are practically the same.
There will be four adults and two children living in the house, and the boiler is going to be piped with an indirect.
I know that doesn't help too much. Do you know of any heat loss calculation freeware out there so I don't just tell him he needs a boiler fired at a little over 2.2 gph?
Just so I have this right (please correct me where I'm wrong):
1.00 GPH #2 Oil has usable of 112,000BTU's (roughly)
A good guesstamate of heat needs: 150,000 BTU's
SSU80 Needs: 212,000 BTU's
Therefore we would need a boiler firing at about 3GPH???
Are you familiar with Buderus products at all? I was looking at Buderus G215 Boiler with a dual-coil indirect (both coils piped together): http://www.buderus.us/files/201001230218160.SM300-400TankBrochure.pdf
FYI: If you use the Solar tank like the one I sent you the link to, you can just pipe the supply from the boiler to the upper coil in the tank, pipe the outlet of the upper coil to the inlet of the lower coil, and then the outlet of the lower coil to the return on the boiler and you will get twice the bang for the buck. If you have 160 supply on a single coil you get 140 out, on a dual-coil that same 160 will come out 120.........
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