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Ingo U
Ingo U, Software Engineer
Category: Homework
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Experience:  Over 25 years experience in software development. Expert in Microsoft .Net, C#, C++, VB, SQL
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In the circuit shown in the figure, the zener diode is rated

Customer Question

In the circuit shown in the figure, the zener diode is rated at 5.6 V and is operating in the zener region. If the voltage from the variable DC power source is 10 V, what would be the measured voltage between points A and B?
Submitted: 1 year ago.
Category: Homework
Expert:  Ingo U replied 1 year ago.
Hello, and thanks for requesting me again.
When a 5.6V Zener diode is operating in the zener region, that tells us the voltage across it will be very very close to 5.6V (-5.6V, strictly speaking, in terms of diode polarity) regardless of current flow.
Thus, the resistor and diode form a kind of voltage divider, and if the supply is set to 10V (points A-C), the voltage between A and B will have to be:
10V - 5.6V = 4.4V
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Expert:  Ingo U replied 1 year ago.
Hi,
just following up, were you able to use my solution?
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Regards,
Ingo U
Expert:  Ingo U replied 1 year ago.
THIS ANSWER IS LOCKED!

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