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# In this exercise, youll re-create the classic race of the

### Resolved Question:

In this exercise, you’ll re-create the classic race of the tortoise and the hare. You’ll use random number generation to develop a simulation of this memorable event.
Our contenders begin the race at “square 1” of 70 squares. Each square represents a possible position along the race course. The finish line is at square 70. The first contender to reach or pass square 70 is rewarded with a pail of fresh carrots and lettuce. The course weaves its way up the side of a slippery mountain, so occasionally the contenders lose ground.
There is a clock that ticks once per second. With each tick of the clock, your program should use function moveTortoise and moveHare to adjust the position of the animals according to the rules in Fig. 8.18. These functions should use pointer-based pass-by-reference to modify the position of the tortoise and the hare.
Use variables to keep track of the positions of the animals (i.e., position numbers are 1–70). Start each animal at position 1 (i.e., the “starting gate”). If an animal slips left before square 1, move the animal back to square 1.
Generate the percentages in the preceding table by producing a random integer i in the range 1 ≤i ≤10. For the tortoise, perform a “fast plod” when 1 ≤ i ≤5, a “slip” when 6 ≤ i ≤7 or a “slow plod” when 8 ≤ i ≤10. Use a similar technique to move the hare.
Begin the race by displaying
BANG !!!!!
AND THEY'RE OFF !!!!!

For each tick of the clock (i.e., each repetition of a loop), display a 70-position line showing the letter T in the tortoise’s position and the letter H in the hare’s position. Occasionally, the contenders land on the same square. In this case, the tortoise bites the hare and your program should display OUCH!!! beginning at that position. All positions other than the T, the H or the OUCH!!! (in case of a tie) should be blank.
After displaying each line, test whether either animal has reached or passed square 70. If so, display the winner and terminate the simulation. If the tortoise wins, display TORTOISE WINS!!! YAY!!! If the hare wins, display Hare wins. Yuch. If both animals win on the same clock tick, you may want to favor the tortoise (the “underdog”), or you may want to display It's a tie. If neither animal wins, perform the loop again to simulate the next tick of the clock.
Submitted: 2 years ago.
Category: Homework
Expert:  LogicPro replied 2 years ago.
Hi,
Welcome here.
My name is XXXXX XXXXX I will help you.
What is the deadline?
Which C++ compiler you are using?
Customer: replied 2 years ago.

Do you need any other information?

Expert:  LogicPro replied 2 years ago.
Yes.
What is the deadline?
Which C++ compiler you are using?
Customer: replied 2 years ago.

Deadline: 11/05 @ 11:55

mingw

netbean ide

Expert:  LogicPro replied 2 years ago.
ok.

Expert:  LogicPro replied 2 years ago.

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Customer: replied 2 years ago.

hi! that's great but, i dont wannna print any dots and when generating a random number we should use random engine that comes with C++ 11

Expert:  LogicPro replied 2 years ago.
What do you want to print instead of dots?
Also I used rand() which is C++ function? If there is something else 'random engine that comes with C++ 11', please provide example
Customer: replied 2 years ago.

2 // Using a C++11 random-number generation engine and distribution
3 // to roll a six-sided die.
4 #include <iostream>
5 #include <iomanip>
6 #include <random> // contains C++11 random number generation features
7 #include <ctime>
8 using namespace std;
9
10 int main()
11 {
12 // use the default random-number generation engine to
13 // produce uniformly distributed pseudorandom int values from 1 to 6
14 default_random_engine engine(static_cast<unsigned int>( time(0) ) );
15 uniform_int_distribution<unsigned int> randomInt( 1, 6 );
16
17 // loop 10 times
18 for ( unsigned int counter = 1; counter <= 10; ++counter )
19 {
20 // pick random number from 1 to 6 and output it
21 cout << setw( 10 ) << randomInt( engine );
22
23 // if counter is divisible by 5, start a new line of output
24 if ( counter % 5 == 0 )
25 cout << endl;
26 } // end for
27 } // end main

instead of dot just blank is ok

Expert:  LogicPro replied 2 years ago.

Customer: replied 2 years ago.

The output shows most of the time the tortoise is not moving.

Customer: replied 2 years ago.

BANG!!!!!

AND THEY'RE OFF!!!!!

T

T

T H

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here the hare is first but it says tortoise wins

Expert:  LogicPro replied 2 years ago.
Could you provide complete requirements in a word document?
Customer: replied 2 years ago.

Now, the program looks fine. Can you simply the body of moveHare, and moveTortoise. We haven't learned : ? Can you do without using these?

Expert:  LogicPro replied 2 years ago.

Tortoise will not move if postion is < 2
Customer: replied 2 years ago.

Expert:  LogicPro replied 2 years ago.
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LogicPro, Engineer
Category: Homework
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Experience: Expert in Java C++ C C# VB Javascript Design SQL HTML
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