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Raj
Raj, Engineer
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You have in your program an ArrayList that contains employee

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Goes without saying these are Java programming questions:


 


You have in your program an ArrayList that contains employee names (strings) in arbitrary order. You need to display the employees ordered alphabetically by name. Provide detailed steps of how you plan to accomplish this task. You do not need to give correct Java code (a detailed pseudocode is sufficient) but indicate which method(s) and which Java class(es) you would use. Suppose that you have an array of baseball scores (type integer) called Scores. The values in the array are ordered from largest to smallest. You need to find the average score, and how many scores are less or equal to the average, and how many are greater than the average. Write a code fragment to accomplish it, or at the very least write a detailed plan (pseudocode).

Hi There,

I will be helping you with the solution.
Can you please post the complete requirement once again.
Also you need Pseudocode or Code in any programming Language?

Thank you
Customer: replied 3 years ago.

Hi! They are two separate questions so don't be confused by trying to answer them both as one:


 


1: You have in your program an ArrayList that contains employee names (strings) in arbitrary order. You need to display the employees ordered alphabetically by name. Provide detailed steps of how you plan to accomplish this task. You do not need to give correct Java code (a detailed pseudocode is sufficient) but indicate which method(s) and which Java class(es) you would use. (Java code is unnecessary but specific Java classes and methods should be listed within the pseudocode to accomplish this)


 


2. Suppose that you have an array of baseball scores (type integer) called Scores. The values in the array are ordered from largest to smallest. You need to find the average score, and how many scores are less or equal to the average, and how many are greater than the average. Write a code fragment to accomplish it, or at the very least write a detailed plan (pseudocode). (This would prefer to write it in Java however, if unable, then pseudocode is acceptable)

No Problem got it.

Let me know the deadline for both the requirements?
Customer: replied 3 years ago.

30 - 45 minutes? Appreciate it :)

Based on Urgency and Amount of work I am sending an Underprice report.
Please check you e-mail registered with us to get the new price for the Question.
Customer: replied 3 years ago.

$60?

I sent underprice for $70
Customer: replied 3 years ago.

I set it for $65, as $70 was not an available option.

Ok No Problem you can add $5 as BONUS after I am done with the Solution.
Are we good here?
Customer: replied 3 years ago.

Yes we are. Looking forward to your reply soon

Yes Almost done with Solution 1.

Just for confirmation : For Part 1 you just need steps how we will sort the Arraylist(employee of type string) in alphabetical order right??
Customer: replied 3 years ago.

That's correct. The ArrayList is initially randomized so the names need to be arranged in alphabetical order.

Ok Got it.
UPDATE:
Solution 1 is done now am working on Solution 2.
Customer: replied 3 years ago.

Understood

SOLUTIONS are ready:

Solution 1:

STEP 1:
To Sort the Arraylist containing the employee names of type String we will make use of Collections class defined inside java.util.Collections.
So We will import that class at the beginning of the code using the below format:
import java.util.Collections;

STEP 2: Than in Collection class we Have a Method name sort() which sorts the specified list into ascending order which will be done using the below command:
Collections.sort(employee);

STEP 3:At the end Arraylist named employee is sorted with employee name sorted in ascending order.

Solution 2:

//Name of File: Baseball.java

class Baseball
{
public static void main(String[] args)
{
int[ ] score = {10,9,7,6,5,5,4,3,3,3,2,0};
int size;
int total = 0;
int average = 0;
int belowAvg = 0;
int aboveAvg = 0;
size = score.length;

//Find the Average Score
for(int i = 0; i < size; i++)
{
total += score[ i ];
}
average = total / size;

//Now calculate the count below Average and above Average
for(int i = 0; i < size; i++)
{
if(score[ i ] <= average)
{
belowAvg++;
}
else
{
aboveAvg++;
}
}

//Display Result.
System.out.println("Number of Team with Score Less or Equal to Average : "+belowAvg);
System.out.println("Number of Team with Score Less or Equal to Average : "+aboveAvg);

}
}

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