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akch2002, Engineer
Category: Homework
Satisfied Customers: 3091
Experience:  Home work expert
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# I need help with FM transmitters.

### Customer Question

I need help with FM transmitters problem #18 only

Attachment: 2013-02-02_004606_hwk.docx

Attachment: 2013-02-02_004637_hwk.docx

Submitted: 3 years ago.
Category: Homework
Expert:  akch2002 replied 3 years ago.
Expert:  akch2002 replied 3 years ago.

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akch2002, Engineer
Category: Homework
Satisfied Customers: 3091
Experience: Home work expert
Customer: replied 3 years ago.

Thank you. My last questions would be for part b why do we multiply peak to peak by 2 and where does the 1000 come from in part e.

Expert:  akch2002 replied 3 years ago.
b)In frequency multiplier, there are one doubler and two triplers. Hence, total multiplication factor is 2*3^2 = 18.
e) Frequency is 11.61kHz= 11.61*1000. This is how factor 1000 is to be considered.
Customer: replied 3 years ago.

Pardon me it was for part c and not b. You multiplied 2*4 Vpp, and why times two?

Expert:  akch2002 replied 3 years ago.
Peak to peak voltage is given and, hence, total variation in voltage is 8 volts. Factor of 2 is coning to take care of tis.
Customer: replied 3 years ago.

Are you sure you're not confusing it with V pk and thus multiplying by 2? You are multiplying by 2 for a 4 V peak to peak? Is my reasoning correct?

Expert:  akch2002 replied 3 years ago.
Yes, I am sure. We are given peak to peak and we have to multiply by 2.

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