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Ryan, Engineer

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Science: If I have 8.2 grams of sugar in 25 ml of water for

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Science: If I have 8.2 grams of sugar in 25 ml of water for my initial solution and transfer 2.5 ml out and then refill the solution to 25 ml what will the final concentration in Moles be? Then if again I have my new solution and now trnasfer 4.5 ml out and then refill the remasining solution up to 25 ml of water, what is my final concentration in moles?

Does the first solution remove any soution. Second should remove 2.5, third should remove 4,5 ml, then 3ml, then 6ml. I need the final concentration of each after each amount is transferred out in (M)

The first value, 0.9582 M, was for the original mix, before any of the solution is removed.

The second value, 0.8624 M, was for the solution after removing 2.5 ml of the first solution.

The third value, 0.7072 M, was for the solution after removing 4.5 ml of the second solution.

The parts about removing 3 ml and 6 ml were not in my previous solution because that information was not included in your original post. Here are the answers for those steps:

Starting with the third solution (0.7072 M), removing 3 ml and then replacing it with water leaves a concentration of:

(0.7072 M)(25 ml - 3 ml) / 25 ml = 0.6223 M

Removing 6 ml of this solution and replacing it with water leaves a concentration of:

(0.6223 M)(25 ml - 6 ml)/ 25 ml = 0.4729 M

In table form, the solutions are:

original solution: 0.9582 M after replacing 2.5 ml: 0.8624 M after replacing 4.5 ml: 0.7072 M after replacing 3 ml: 0.6223 M after replacing 6 ml: 0.4729 M

Thanks,

Ryan

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So can I make the assumption that as the sugar shrinks from the solution the weight in grams rises but the molecular weight in moles decreases? Is that right?